Java函数式编程中高阶函数与方法引用的区别？

import java.util.Arrays;
import java.util.List;

public class HighOrderFunctionExample {

    public static void main(String[] args) {
        List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5);

        // 高阶函数 map，接收一个函数并将其应用于集合中的每个元素
        List<Integer> squaredNumbers = map(numbers, x -> x * x);

        System.out.println(squaredNumbers); // [1, 4, 9, 16, 25]
    }

    private static <T, R> List<R> map(List<T> list, Function<T, R> function) {
        List<R> result = new ArrayList<>();
        for (T t : list) {
            result.add(function.apply(t));
        }
        return result;
    }
}

import java.util.Arrays;
import java.util.List;

public class MethodReferenceExample {

    public static void main(String[] args) {
        List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5);

        // 方法引用，类似于 lambda 表达式
        List<Integer> squaredNumbers = map(numbers, Integer::square);

        System.out.println(squaredNumbers); // [1, 4, 9, 16, 25]
    }

    private static <T, R> List<R> map(List<T> list, Function<T, R> function) {
        List<R> result = new ArrayList<>();
        for (T t : list) {
            result.add(function.apply(t));
        }
        return result;
    }
}