$arr = array( array( 'imp' => 1000, 'clk' => 100, 'date' => 20150601 ), array( 'imp' => 1002, 'clk' => 102, 'date' => 20150602 ), array( 'imp' => 1003, 'clk' => 103, 'date' => 20150601 ) );
求这个数组里相同日期的曝光总和、点击总和,用最简洁的代码表示出来
imp 曝光
clk 点击
date 日期
$arr = array( array( 'imp' => 1000, 'clk' => 100, 'date' => 20150601 ), array( 'imp' => 1002, 'clk' => 102, 'date' => 20150602 ), array( 'imp' => 1003, 'clk' => 103, 'date' => 20150601 ) );
求这个数组里相同日期的曝光总和、点击总和,用最简洁的代码表示出来
imp 曝光
clk 点击
date 日期
php$a=array(); foreach($arr as $v){ $a[$v['date']]['clk']+=$v['clk']; $a[$v['date']]['imp']+=$v['imp']; } print_r($a);
php$res=[]; foreach ($arr as $key => $value) { $res[$value['date']] =array( 'imp' =>isset($res[$value['date']]) ? $res[$value['date']]['imp']+$value['imp'] : $value['imp'], 'clk' =>isset($res[$value['date']]) ? $res[$value['date']]['clk']+$value['clk'] : $value['clk'], 'date' =>$value['date'] ); } print_r(array_values($res)); Array ( [0] => Array ( [imp] => 2003 [clk] => 203 [date] => 20150601 ) [1] => Array ( [imp] => 1002 [clk] => 102 [date] => 20150602 ) )
$tmp = array(); foreach($arr as $k => $v) { $tmp[$k] = $v['date']; } $tmp = array_unique($tmp); /* 去重后得 Array ( [0] => 20150601 [1] => 20150602 ) */ $tmp2 = array(); foreach($tmp as $k => $v) { $tmp2[$v]['imp'] = 0; $tmp2[$v]['clk'] = 0; } /* 初始化得 Array ( [20150601] => Array ( [imp] => 0 [clk] => 0 ) [20150602] => Array ( [imp] => 0 [clk] => 0 ) ) */ foreach($tmp as $k => $v) { foreach($arr as $k2 => $v2) { if($v == $v2['date']) { $tmp2[$v]['imp'] += $v2['imp']; $tmp2[$v]['clk'] += $v2['clk']; } } } print_r($tmp2); /* 求和得 Array ( [20150601] => Array ( [imp] => 2003 [clk] => 203 ) [20150602] => Array ( [imp] => 1002 [clk] => 102 ) ) */
来个reduce版本
0, 'clk' => 0 ]); print_r($result);
http://3v4l.org/58v94
专业问题。。学习了
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