如何将列表中相同前三列的数据合并到第四列？

def combine_list(list1, list2):
    list0 = list1[:]
    if list1[0] == list2[0] and list1[1] == list2[1] and list1[2] == list2[2]:
        list_temp = [list1[3], list2[3]]
        list0[3] = list_temp
        return list0
    else:
        pass

o_new = o[:]

for i in range(1, len(o)):
    temp = combine_list(o[j], o[i])
    if temp is not none:
        o_new.append(temp)
        o_new.remove(o[j])
        o_new.remove(o[i])
        if i == 3:
            j += 1
            i = 1
        if j == 3:
            break

print(o_new)

def combine_list(list1, list2):
    list0 = list1[:]
    if list1[0] == list2[0] and list1[1] == list2[1] and list1[2] == list2[2]:
        list_temp = [list1[3], list2[3]]
        list0[3] = list_temp
        return list0
    else:
        pass

o = []
a = ['cmd', ['opt1', 'opt2'], '12.2(2)SE', 'Cat3560']
b = ['cmd', ['opt1', 'opt2'], '12.2(2)SE', 'Cat4500']
c = ['cmd', ['opt1', 'opt2', 'opt3', 'opt4'], '12.3(2)SE', 'Cat3560']
d = ['cmd', ['opt1', 'opt2', 'opt3'], '12.4(2)SE', 'Cat3560']
o.append(a)
o.append(b)
o.append(c)
o.append(d)

o_new = o[:]

j = 0
for i in range(1, len(o)):
    temp = combine_list(o[j], o[i])
    if temp is not None:
        o_new.append(temp)
        o_new.remove(o[j])
        o_new.remove(o[i])
        if i == 3:
            j += 1
            i = 1
        if j == 3:
            break

print(o_new)