
五子棋机器人,简化代码
问题:
我花了几天的时间用vue写了一个五子棋,与机器人对战
但是我感觉里面代码很多重复的部分,想要简化写法,希望大家帮我看看
重复代码:
function airPoint() {
//机器人四个连在了一起,那应该要放四个旁边
console.log(fourDetial, 'fourDetial')
if (fourDetial && JSON.stringify(fourDetial) !== '{}') {
if (fourDetial.type === 1) {
if (fourDetial.geyi) {
for (let i = fourDetial.x; i > fourDetial.x - fourDetial.times + 1; i--) {
if (boxs.value[i][fourDetial.y].place === 0) {
boxs.value[i][fourDetial.y].place = 2
fourDetial = determineEquare3(4, 2, { x: i, y: fourDetial.y, place: 2 })
airPlace.push((i) * row.value + fourDetial.y)
curUser.value = 1
return
}
}
}
else
if (boxs.value[fourDetial.x + 1]?.[fourDetial.y]?.place === 0) {
boxs.value[fourDetial.x + 1][fourDetial.y].place = 2
fourDetial = determineEquare3(4, 2, { x: fourDetial.x + 1, y: fourDetial.y, place: 2 })
airPlace.push((fourDetial.x + 1) * row.value + fourDetial.y)
curUser.value = 1
return
} else if (boxs.value[fourDetial.x - fourDetial.times]?.[fourDetial.y]?.place === 0) {
boxs.value[fourDetial.x - fourDetial.times][fourDetial.y].place = 2
fourDetial = determineEquare3(4, 2, { x: fourDetial.x - fourDetial.times, y: fourDetial.y, place: 2 })
airPlace.push((fourDetial.x - fourDetial.times) * row.value + fourDetial.y)
curUser.value = 1
return
}
} else if (fourDetial.type === 2) {
if (fourDetial.geyi) {
for (let j = fourDetial.y; j > fourDetial.y - fourDetial.times + 1; j--) {
if (boxs.value[fourDetial.x][j].place === 0) {
boxs.value[fourDetial.x][j].place = 2
fourDetial = determineEquare3(4, 2, { x: fourDetial.x, y: j, place: 2 })
airPlace.push((fourDetial.x) * row.value + j)
curUser.value = 1
return
}
}
}
else if (boxs.value[fourDetial.x]?.[fourDetial.y + 1]?.place === 0) {
boxs.value[fourDetial.x][fourDetial.y + 1].place = 2
fourDetial = determineEquare3(4, 2, { x: fourDetial.x, y: fourDetial.y + 1, place: 2 })
airPlace.push((fourDetial.x) * row.value + fourDetial.y + 1)
curUser.value = 1
return
} else if (boxs.value[fourDetial.x]?.[fourDetial.y - fourDetial.times]?.place === 0) {
boxs.value[fourDetial.x][fourDetial.y - fourDetial.times].place = 2
fourDetial = determineEquare3(4, 2, { x: fourDetial.x, y: fourDetial.y - fourDetial.times, place: 2 })
airPlace.push((fourDetial.x) * row.value + fourDetial.y - fourDetial.times)
curUser.value = 1
return
}
} else if (fourDetial.type === 3) {
if (fourDetial.geyi) {
let i
for (let j = fourDetial.y - 1; j > fourDetial.y - fourDetial.times + 1; j--) {
i = fourDetial.x - (fourDetial.y - j)
if (boxs.value[i]?.[j]?.place === 0) {
boxs.value[i][j].place = 2
fourDetial = determineEquare3(4, 2, { x: i, y: j, place: 2 })
airPlace.push((i) * row.value + j)
curUser.value = 1
return
}
}
}
else
if (boxs.value[fourDetial.x + 1]?.[fourDetial.y + 1]?.place === 0) {
boxs.value[fourDetial.x + 1][fourDetial.y + 1].place = 2
fourDetial = determineEquare3(4, 2, { x: fourDetial.x + 1, y: fourDetial.y + 1, place: 2 })
airPlace.push((fourDetial.x + 1) * row.value + fourDetial.y + 1)
curUser.value = 1
return
} else if (boxs.value[fourDetial.x - fourDetial.times]?.[fourDetial.y - fourDetial.times]?.place === 0) {
boxs.value[fourDetial.x - fourDetial.times][fourDetial.y - fourDetial.times].place = 2
fourDetial = determineEquare3(4, 2, { x: fourDetial.x - fourDetial.times, y: fourDetial.y - fourDetial.times, place: 2 })
airPlace.push((fourDetial.x - fourDetial.times) * row.value + fourDetial.y - fourDetial.times)
curUser.value = 1
return
}
} else if (fourDetial.type === 4) {
if (fourDetial.geyi) {
let i
for (let j = fourDetial.y; j < fourDetial.y + fourDetial.times - 1; j++) {
i = fourDetial.x - (j - fourDetial.y)
if (boxs.value[i]?.[j]?.place === 0) {
boxs.value[i][j].place = 2
fourDetial = determineEquare3(4, 2, { x: i, y: j, place: 2 })
airPlace.push((i) * row.value + j)
curUser.value = 1
return
}
}
}
else if (boxs.value[fourDetial.x + 1]?.[fourDetial.y - 1]?.place === 0) {
boxs.value[fourDetial.x + 1][fourDetial.y - 1].place = 2
fourDetial = determineEquare3(4, 2, { x: fourDetial.x + 1, y: fourDetial.y - 1, place: 2 })
airPlace.push((fourDetial.x + 1) * row.value + fourDetial.y - 1)
curUser.value = 1
return
} else if (boxs.value[fourDetial.x - fourDetial.times]?.[fourDetial.y + fourDetial.times]?.place === 0) {
boxs.value[fourDetial.x - fourDetial.times][fourDetial.y + fourDetial.times].place = 2以上就是五子棋机器人代码优化:如何简化重复代码?的详细内容,更多请关注php中文网其它相关文章!
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