如何通过提取重复代码为小函数，简化五子棋机器人的代码？

function airPoint() {
  const directions = [
    [0, 1], [1, 0], [1, 1], [1, -1] // 四个方向：水平、垂直、两个对角线
  ];

  // 检查是否有四个连在一起的情况
  if (!isEmptyObject(fourDetial)) {
    const { type, geyi, x, y, times } = fourDetial;

    if (geyi) {
      for (let i = x; i > x - times + 1; i--) {
        if (checkAndPlace(i, y)) {
          return;
        }
      }
    } else {
      for (const [dx, dy] of directions) {
        const newX = x + dx * times;
        const newY = y + dy * times;

        if (checkAndPlace(newX, newY)) {
          return;
        }
      }
    }
  }

  // 检查是否有阻挡用户的情况
  const temp = determineEquare3();
  if (temp) {
    const { type, geyi, x, y, times } = temp;

    if (geyi) {
      for (let i = x; i > x - times + 1; i--) {
        if (checkAndPlace(i, y)) {
          return;
        }
      }
    } else {
      for (const [dx, dy] of directions) {
        const newX = x + dx * times;
        const newY = y + dy * times;

        if (checkAndPlace(newX, newY)) {
          return;
        }
      }
    }
  } else {
    // 企图完成五个连线
    airFiveLine();
  }

  curUser.value = 1;
}