PDO如何绑定IN()语句的array变量

$ids = array(2344, 5523, 9332);
$st = $pdo->prepare('SELECT * FROM table_name WHERE id IN (:id)');
$st->bindParam('id', $ids);
$st->execute();

$ids = array(2344, 5523, 9332);
$st = $pdo->prepare('SELECT * FROM table_name WHERE id IN (:id)');
$st->bindParam('id', $ids);
$st->execute();

$ids = array(2344, 5523, 9332);
// 过滤ids略
$in = implode(',',$ids); 
$st = $pdo->prepare('SELECT * FROM table_name WHERE id IN ('.$in.')');
$st->execute();

$ids = array(2344, 5523, 9332);
// 自动构造多个?号略
$st = $pdo->prepare('SELECT * FROM table_name WHERE id IN (?,?,?)');
foreach ($ids as $k => $id)
    $st->bindValue(($k+1), $id);
$st->execute();

<code><?php
define('DBHost', '127.0.0.1');
define('DBName', 'Database');
define('DBUser', 'root');
define('DBPassword', '');
require(dirname(__FILE__)."/src/PDO.class.php");
$DB = new Db(DBHost, DBName, DBUser, DBPassword);
?>
</code>

<code><?php
$DB->query("SELECT * FROM fruit WHERE name IN (?)",array('apple','banana'));
?>
</code>