溪流帕拉拉斯

List<Integer> numbers = List.of(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
int sum = numbers.parallelStream()
                 .reduce(0, Integer::sum);
System.out.println("并行流求和结果：" + sum);

List<Integer> numbers = List.of(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
List<Integer> result = numbers.parallelStream()
                              .filter(n -> n % 2 == 0) // 过滤偶数
                              .collect(Collectors.toList());
System.out.println("结果：" + result);

List<Integer> numbers = List.of(1, 5, 2, 8, 3, 9, 4, 7, 6, 10);
Optional<Integer> max = numbers.parallelStream()
                               .reduce(Integer::max); // 使用 max 查找最大值
max.ifPresent(System.out::println); // 打印最大值

List<String> words = List.of("apple", "banana", "cherry", "date", "elderberry");
long count = words.parallelStream()
                  .filter(word -> word.length() > 5)
                  .count();
System.out.println("长度大于5的单词数量：" + count);