PHP如何高效处理JSON多层嵌套数据并循环输出特定信息？-php教程-PHP中文网

PHP如何高效处理JSON多层嵌套数据并循环输出特定信息？

花韻仙語

发布： 2025-02-20 09:18:18

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php如何高效处理json多层嵌套数据并循环输出特定信息？

PHP解析并输出JSON多层嵌套数据

处理JSON多层嵌套数据并提取特定信息，需要巧妙地运用PHP的数组操作功能。以下示例演示如何高效地完成此任务：

示例JSON数据：

<code class="json">[
  {
    "school": "A校",
    "grade": "一年级",
    "class": "一班",
    "students": [
      "男#25",
      "女#29"
    ]
  },
  {
    "school": "A校",
    "grade": "一年级",
    "class": "二班",
    "students": [
      "男#30",
      "女#22"
    ]
  }
]</code>

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目标HTML输出结构：

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查看详情

<code class="html"><h1>学校</h1><h2>年级</h2><h3>班级</h3>
<div>
  <ul>
    <li>性别：人数</li>
    <li>性别：人数</li>
  </ul>
</div></code>

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PHP代码实现：

<code class="php">$jsonData = '[
  {
    "school": "A校",
    "grade": "一年级",
    "class": "一班",
    "students": [
      "男#25",
      "女#29"
    ]
  },
  {
    "school": "A校",
    "grade": "一年级",
    "class": "二班",
    "students": [
      "男#30",
      "女#22"
    ]
  }
]';

$jsonArray = json_decode($jsonData, true);

foreach ($jsonArray as $schoolData) {
  echo "<h1>" . $schoolData['school'] . " " . $schoolData['grade'] . " " . $schoolData['class'] . "</h1>";
  echo "<div><ul>";
  foreach ($schoolData['students'] as $studentData) {
    list($gender, $count) = explode('#', $studentData);
    echo "<li>" . $gender . "：" . $count . "</li>";
  }
  echo "</ul></div>";
}</code>

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代码解释：