如何使用Java将List中Item2.num为0的元素排序到末尾？

items.sort((o1, o2) -> {
    int num1 = o1.getItem2().getNum();
    int num2 = o2.getItem2().getNum();

    if (num1 == 0 && num2 != 0) {
        return 1; // 将num1为0的元素排在后面
    } else if (num1 != 0 && num2 == 0) {
        return -1; // 将num2为0的元素排在后面
    } else {
        return 0; // num1和num2都为0或都不为0，保持原有顺序
    }
});

import java.util.ArrayList;
import java.util.List;
import java.util.Random;

public class ItemSorter {

    public static void main(String[] args) {
        List<Item> items = generateSampleData();
        System.out.println("排序前:");
        printNums(items);

        items.sort((o1, o2) -> {
            int num1 = o1.getItem2().getNum();
            int num2 = o2.getItem2().getNum();

            if (num1 == 0 && num2 != 0) {
                return 1;
            } else if (num1 != 0 && num2 == 0) {
                return -1;
            } else {
                return 0;
            }
        });


        System.out.println("\n排序后:");
        printNums(items);
    }

    private static void printNums(List<Item> items) {
        for (Item item : items) {
            System.out.print(item.getItem2().getNum() + " ");
        }
        System.out.println();
    }

    private static List<Item> generateSampleData() {
        List<Item> items = new ArrayList<>();
        Random random = new Random();
        for (int i = 0; i < 10; i++) {
            items.add(new Item(i, "Item " + i, new Item2(i, random.nextInt(3)))); // 生成0-2之间的随机数
        }
        return items;
    }
}

class Item {
    private long id;
    private String title;
    private Item2 item2;

    public Item(long id, String title, Item2 item2) {
        this.id = id;
        this.title = title;
        this.item2 = item2;
    }

    public Item2 getItem2() {
        return item2;
    }
}

class Item2 {
    long id;
    int num;

    public Item2(long id, int num) {
        this.id = id;
        this.num = num;
    }

    public int getNum() {
        return num;
    }
}