JavaScript数组嵌套匹配替换：如何根据一个数组的值替换另一个数组中嵌套对象的元素？

arr = [
    {
        sk: [
            { name: '数据1', value: '200' },
            { name: '数据2', value: '300' },
            { name: '数据3', value: '400' },
        ],
    },
    {
        sk: [
            { name: '数据5', value: '500' },
            { name: '数据6', value: '600' },
            { name: '数据7', value: '700' },
        ],
    },
];

arr2 = {
    name: '数据555',
    val: [200, 300, 500],
};

const updateNestedArray = (arr, arr2) => {
  // 确保arr2.val是一个数组并且arr存在
  if (!Array.isArray(arr2.val) || !arr) return arr;

  const valSet = new Set(arr2.val.map(Number)); // 使用Set提高查找效率

  return arr.map(item => {
    if (!item.sk || !Array.isArray(item.sk)) return item; // 处理空或无效的sk属性

    item.sk = item.sk.map(obj => ({
      ...obj,
      name: valSet.has(Number(obj.value)) ? arr2.name : obj.name // 条件替换
    }));
    return item;
  });
};

let result = updateNestedArray(arr, arr2);
console.log(result);

[
  {
    sk: [
      { name: '数据555', value: '200' },
      { name: '数据555', value: '300' },
      { name: '数据3', value: '400' },
    ],
  },
  {
    sk: [
      { name: '数据555', value: '500' },
      { name: '数据6', value: '600' },
      { name: '数据7', value: '700' },
    ],
  },
];