如何用JavaScript高效查找三维空间中距离目标点最近的坐标点，以及判断该点在线段的哪个位置？

const target = [-11.034364525537594, 1, 24.978631454302235];
const arr = [
  [-4.167605156499352, 1, 16.43419792128068],
  [-13.60939928892453, 1, 28.216932747654095],
  [-16.84770058227477, 1, 27.514650539457307]
];

const nearestPoint = arr.reduce((nearest, point, index) => {
  const distanceSquared = point.reduce((sum, coord, i) => sum + Math.pow(coord - target[i], 2), 0);
  if (index === 0 || distanceSquared < nearest.distanceSquared) {
    return { point, index, distanceSquared };
  }
  return nearest;
}, { distanceSquared: Infinity });

console.log("Nearest point:", nearestPoint.point, "Index:", nearestPoint.index);

function isCollinear(p1, p2, p3, precision = 10) {
  const fixed = num => parseFloat(num.toFixed(precision));
  return fixed((p2[1] - p1[1]) * (p3[0] - p2[0])) === fixed((p3[1] - p2[1]) * (p2[0] - p1[0])) &&
         fixed((p2[2] - p1[2]) * (p3[0] - p2[0])) === fixed((p3[2] - p2[2]) * (p2[0] - p1[0])) &&
         fixed((p2[2] - p1[2]) * (p3[1] - p2[1])) === fixed((p3[2] - p2[2]) * (p2[1] - p1[1]));
}

function findSegmentPosition(point, segment) {
  if (isCollinear(segment[0], segment[1], point)) {
    //Further checks to determine exact position on the segment could be added here if needed (e.g., using dot product).
    return "On segment";
  }
  return "Not on segment";
}

const segment = [[-5, 0, 10], [5, 0, 20]];
const pointOnSegment = [0, 0, 15];
const pointOffSegment = [0, 10, 15];

console.log(findSegmentPosition(pointOnSegment, segment)); // Output: On segment
console.log(findSegmentPosition(pointOffSegment, segment)); // Output: Not on segment