JavaScript数组对象比较：如何高效地判断两个包含对象的数组是否相同？

const arr1 = [
    {id:1, name:"小明"},
    {id:2, name:"小红"},
    {id:3, name:"小花"},
    {id:4, name:"小强"}
];

const arr2 = [
    {id:2, name:"小红"},
    {id:3, name:"小花"},
    {id:4, name:"小强"}
];

const _ = require('lodash'); // 需要安装lodash库: npm install lodash

const arr1 = [ /* ... */ ];
const arr2 = [ /* ... */ ];

const commonObjects = _.intersectionWith(arr1, arr2, _.isEqual);

// commonObjects 将包含所有在 arr1 和 arr2 中都存在的对象
console.log(commonObjects); // 输出匹配的对象

function deepCompare(obj1, obj2) {
  if (typeof obj1 !== 'object' || typeof obj2 !== 'object') {
    return obj1 === obj2;
  }
  const keys1 = Object.keys(obj1);
  const keys2 = Object.keys(obj2);
  if (keys1.length !== keys2.length) {
    return false;
  }
  for (let key of keys1) {
    if (!deepCompare(obj1[key], obj2[key])) {
      return false;
    }
  }
  return true;
}

// 使用自定义比较函数
const commonObjects = arr1.filter(obj1 => arr2.some(obj2 => deepCompare(obj1, obj2)));