Go语言如何计算一组数字的AC值（数字复杂度）？

package main

import (
    "fmt"
    "math"
    "sort"
)

func abs(x int) int {
    return int(math.Abs(float64(x)))
}

func calculateAC(data []int) int {
    n := len(data)
    if n < 2 {
        return 0 // 少于两个数字，AC值为0
    }

    // 计算所有数字对之间的差值
    diffs := make([]int, 0)
    for i := 0; i < n; i++ {
        for j := i + 1; j < n; j++ {
            diffs = append(diffs, abs(data[i]-data[j]))
        }
    }

    // 去除重复的差值
    sort.Ints(diffs)
    uniqueDiffs := make([]int, 0)
    if len(diffs) > 0 {
        uniqueDiffs = append(uniqueDiffs, diffs[0])
        for i := 1; i < len(diffs); i++ {
            if diffs[i] != diffs[i-1] {
                uniqueDiffs = append(uniqueDiffs, diffs[i])
            }
        }
    }


    return len(uniqueDiffs) - (n - 1)
}

func main() {
    data := []int{1, 3, 33, 67, 88}
    acValue := calculateAC(data)
    fmt.Printf("The AC value of %v is: %d\n", data, acValue)
}