如何用PHP和CURL高效采集新闻列表及详情信息？

$html = '<div class="box list channel max-border list-text-my">
<ul><li><a href="https://www.php.cn/link/b999a556e5f6186b8cba2dd848c22711" title="">[2022-12-13]新闻1</a></li>
    <li><a href="https://www.php.cn/link/7c1373b8fec010dba9b2cf06e7b232a7" title="">[2022-12-13]新闻2</a></li>
    <li><a href="https://www.php.cn/link/afe7064469e1509a007b92118aee4524" title="">[2022-12-13]新闻3</a></li>
</ul></div>';

preg_match_all('/<a href="https://www.php.cn/link/01bebc8e971d09cb90cf5756b340f24c">(.*?)<\/a>/s', $html, $matches);

$newslist = [];
$base_url = 'http://www.xx.com/news'; //  需根据实际情况修改网站基础URL

foreach ($matches[1] as $key => $relativepath) {
    $newslist[] = [
        'title' => trim($matches[2][$key]),
        'url' => $base_url . $relativepath
    ];
}

print_r($newslist);

foreach ($newsList as $news) {
    $ch = curl_init($news['url']);
    // ... (此处添加CURL配置代码，例如设置超时时间、用户代理等) ...

    $detailHtml = curl_exec($ch);
    curl_close($ch);

    // 使用正则表达式提取新闻内容
    preg_match('/<div class="content text-xs">(.*?)<\/div>/s', $detailHtml, $contentMatch);
    $newsContent = isset($contentMatch[1]) ? $contentMatch[1] : '';

    echo "标题：" . $news['title'] . "\n";
    echo "链接：" . $news['url'] . "\n";
    echo "内容：" . $newsContent . "\n\n";
}