如何简化Vue中五子棋游戏机器人下棋逻辑的重复代码？

// 定义棋盘方向
const directions = [
  [0, 1], [1, 0], [1, 1], [-1, 1] // 水平、垂直、正对角线、反对角线
];

// 检查指定方向上是否有连子
function checkLine(board, x, y, direction, player) {
  let count = 0;
  for (let i = 1; ; i++) {
    const newX = x + direction[0] * i;
    const newY = y + direction[1] * i;
    if (newX < 0 || newX >= board.length || newY < 0 || newY >= board[0].length || board[newX][newY] !== player) {
      break;
    }
    count++;
  }
  return count;
}

// 计算指定位置的得分
function calculateScore(board, x, y, player) {
  let score = 0;
  for (const direction of directions) {
    const count = checkLine(board, x, y, direction, player) + checkLine(board, x, y, [-direction[0], -direction[1]], player) -1; // 减1避免重复计数自身
    if (count >= 4) { // 五子连珠或更多
      score += 10000; // 设置高分值
    } else if (count === 3) {
      score += 100;
    } else if (count === 2) {
      score += 10;
    }
  }
  return score;
}

// AI下棋函数
function aiMove(board) {
  let bestScore = -Infinity;
  let bestMove = null;
  for (let x = 0; x < board.length; x++) {
    for (let y = 0; y < board[0].length; y++) {
      if (board[x][y] === 0) { // 空位置
        board[x][y] = 2; // AI玩家代号为2
        const score = calculateScore(board, x, y, 2);
        board[x][y] = 0; // 还原棋盘
        if (score > bestScore) {
          bestScore = score;
          bestMove = { x, y };
        }
      }
    }
  }
  return bestMove;
}