Java String类equals方法的工作机制是什么？-java教程-PHP中文网

Java String类equals方法的工作机制是什么？

碧海醫心

发布： 2025-03-20 10:14:01

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探究java string类equals方法的工作机制

在学习java string类的equals方法时，我们经常会遇到一些困惑，尤其是当深入到源码时，会发现一些不易理解的现象。今天我们将深入探讨jdk18环境下string类的equals方法的内部逻辑，揭示其中的奥秘。

问题描述

在使用断点调试时，观察到了以下现象：

问题1：

return (anobject instanceof string astring)
       && (!compact_strings || this.coder == astring.coder)
       && stringlatin1.equals(value, astring.value);

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这个逻辑似乎在调试过程中循环运行。而且，有时即使字符相同，如"a".equals("a")时，value与astring.value的数组长度也会不同。

问题2：

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对于"a".equals(new string("a"));，调试时发现传递的参数如图所示：
[参数图像]
对于"a".equals("a");，调试时发现传递的参数如图所示：
[参数图像]

这两个例子中，参数在传递到equals方法后，似乎并不总是如预期的"a"。

解答

让我们从string类的源码开始，逐步理解这些现象。首先，关于compact_strings的定义和说明：

    /**
     * if string compaction is disabled, the bytes in {@code value} are
     * always encoded in utf16.
     *
     * for methods with several possible implementation paths, when string
     * compaction is disabled, only one code path is taken.
     *
     * the instance field value is generally opaque to optimizing jit
     * compilers. therefore, in performance-sensitive place, an explicit
     * check of the static boolean {@code compact_strings} is done first
     * before checking the {@code coder} field since the static boolean
     * {@code compact_strings} would be constant folded away by an
     * optimizing jit compiler. the idioms for these cases are as follows.
     *
     * for code such as:
     *
     *    if (coder == latin1) { ... }
     *
     * can be written more optimally as
     *
     *    if (coder() == latin1) { ... }
     *
     * or:
     *
     *    if (compact_strings && coder == latin1) { ... }
     *
     * an optimizing jit compiler can fold the above conditional as:
     *
     *    compact_strings == true  => if (coder == latin1) { ... }
     *    compact_strings == false => if (false)           { ... }
     *
     * @implnote
     * the actual value for this field is injected by jvm. the static
     * initialization block is used to set the value here to communicate
     * that this static final field is not statically foldable, and to
     * avoid any possible circular dependency during vm initialization.
     */
    static final boolean compact_strings;

    static {
        compact_strings = true;
    }

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从这段说明可以看出，如果compact_strings为false，value将始终使用utf16编码。这个设置和coder字段密切相关。

接下来，我们看看coder的定义：

    /**
     * the identifier of the encoding used to encode the bytes in
     * {@code value}. the supported values in this implementation are
     *
     * latin1
     * utf16
     *
     * @implnote this field is trusted by the vm, and is a subject to
     * constant folding if string instance is constant. overwriting this
     * field after construction will cause problems.
     */
    private final byte coder;

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coder有两个可能的值，分别表示latin1和utf16。我们可以找到与coder同名的方法：

    byte coder() {
        return compact_strings ? coder : utf16;
    }

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因此，条件(!compact_strings || this.coder == astring.coder)的意义就很明确了：

如果compact_strings == false，就使用utf16编码，继续检查下一个条件。如果条件不成立，就检查coder是否相同，如果不相同，直接返回false。我们可以用手写代码来理解这个逻辑：

boolean flag = false;
if (!compact_strings) {
    flag = true; // 根据 compact_strings 的说明，这种情况下使用 utf16，忽略 coder 值
} else if (this.coder == astring.coder) {
    flag = true; // 说明 coder 一致
}

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然后，stringlatin1.equals(value, astring.value)条件中，内部数据value使用latin1编码规则进行比较。value的定义如下：

    /**
     * The value is used for character storage.
     *
     * @implNote This field is trusted by the VM, and is a subject to
     * constant folding if String instance is constant. Overwriting this
     * field after construction will cause problems.
     *
     * Additionally, it is marked with {@link Stable} to trust the contents
     * of the array. No other facility in JDK provides this functionality (yet).
     * {@link Stable} is safe here, because value is never null.
     */
    @Stable
    private final byte[] value;

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因此，equals方法的完整逻辑如下：