join update vs sub-selects update-mysql教程-PHP中文网

join update vs sub-selects update

php中文网

发布： 2016-06-07 16:10:51

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开发说使用多表关联进行更新的时候发现没有正确的更新记录（事后发现是条件问题），之前一直没怎么使用关联更新，这次看了下，发现了个问题，当返回多行记录的时候并不会像传统的子查询更新那样报错，而是随机选择一个记录进行更新（貌似最后一个？）因此

开发说使用多表关联进行更新的时候发现没有正确的更新记录（事后发现是条件问题），之前一直没怎么使用关联更新，这次看了下，发现了个问题，当返回多行记录的时候并不会像传统的子查询更新那样报错，而是随机选择一个记录进行更新（貌似最后一个？）
因此，虽然关联更新会快很多，但是要考虑的这个不确定带来的隐患。

gtlions=# create table joinupdate1(id int,name varchar(20));
NOTICE:  Table doesn't have 'DISTRIBUTED BY' clause -- Using column named 'id' as the Greenplum Database data distribution key for this table.
HINT:  The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
CREATE TABLE
gtlions=# create table joinupdate2(id int,name varchar(20));
NOTICE:  Table doesn't have 'DISTRIBUTED BY' clause -- Using column named 'id' as the Greenplum Database data distribution key for this table.
HINT:  The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
CREATE TABLE
gtlions=# insert into  joinupdate1 values(1,'a');
INSERT 0 1
gtlions=# insert into  joinupdate1 values(2,'b');
INSERT 0 1
gtlions=# insert into  joinupdate2 values(1,'b');
INSERT 0 1
gtlions=# insert into  joinupdate2 values(2,'b');
INSERT 0 1
gtlions=# truncate table joinupdate2;
TRUNCATE TABLE
gtlions=# insert into  joinupdate2 values(1,'c');
INSERT 0 1
gtlions=# insert into  joinupdate2 values(2,'d'); 
INSERT 0 1
gtlions=# select * from joinupdate1;
 id | name 
----+------
  1 | a
  2 | b
(2 rows)

gtlions=# select * from joinupdate2;
 id | name 
----+------
  1 | c
  2 | d
(2 rows)

gtlions=# begin;
BEGIN
gtlions=# update joinupdate1 set name=(select name from joinupdate2 where joinupdate1.id=joinupdate2.id);
UPDATE 2
gtlions=# select * from joinupdate1;
 id | name 
----+------
  1 | c
  2 | d
(2 rows)

gtlions=# rollback;
ROLLBACK
gtlions=# end;
WARNING:  there is no transaction in progress
COMMIT
gtlions=# select * from joinupdate1;
 id | name 
----+------
  1 | a
  2 | b
(2 rows)

gtlions=# begin;
BEGIN
gtlions=# update joinupdate1 set name=joinupdate2.name from joinupdate2 where joinupdate1.id=joinupdate2.id;
UPDATE 2
gtlions=# select * from joinupdate1;
 id | name 
----+------
  1 | c
  2 | d
(2 rows)

gtlions=# rollback;
ROLLBACK
gtlions=# insert into joinupdate2 values(1,'e');
INSERT 0 1
gtlions=# begin;
BEGIN
gtlions=# update joinupdate1 set name=(select name from joinupdate2 where joinupdate1.id=joinupdate2.id);
ERROR:  more than one row returned by a subquery used as an expression  (seg0 slice2 h1:40000 pid=14123)
gtlions=# rollback;
ROLLBACK
gtlions=# begin;
BEGIN
gtlions=# update joinupdate1 set name=joinupdate2.name from joinupdate2 where joinupdate1.id=joinupdate2.id;
UPDATE 2
gtlions=# select * from joinupdate1;
 id | name 
----+------
  1 | e
  2 | d
(2 rows)

gtlions=# update joinupdate1 set name=joinupdate2.name from joinupdate2 where joinupdate1.id=joinupdate2.id;
UPDATE 2
gtlions=# select * from joinupdate1;
 id | name 
----+------
  1 | e
  2 | d
(2 rows)

gtlions=# update joinupdate1 set name=joinupdate2.name from joinupdate2 where joinupdate1.id=joinupdate2.id;
UPDATE 2
gtlions=# select * from joinupdate1;
 id | name 
----+------
  1 | e
  2 | d
(2 rows)

gtlions=# insert into joinupdate2 values(1,'f');
INSERT 0 1
gtlions=# update joinupdate1 set name=joinupdate2.name from joinupdate2 where joinupdate1.id=joinupdate2.id;
UPDATE 2
gtlions=# select * from joinupdate1;
 id | name 
----+------
  1 | f
  2 | d
(2 rows)

gtlions=# rollback;
ROLLBACK

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