mysql中 innodb表的count()优化-mysql教程-PHP中文网

作/译者：叶金荣（imysql#imysql.com），来源： http://imysql.com，欢迎转载。起因：在innodb表上做count(*)统计实在是太慢了，因此想办法看能不能再快点。现象：先来看几个测试案例，如下一、 sbtest 表上的测试 show create table sbtest\G***********

作/译者：叶金荣（imysql#imysql.com>），来源： http://imysql.com，欢迎转载。

起因：在innodb表上做count(*)统计实在是太慢了，因此想办法看能不能再快点。
现象：先来看几个测试案例，如下
一、 sbtest 表上的测试

show create table sbtest\G
*************************** 1. row ***************************
Table: sbtest
Create Table: CREATE TABLE `sbtest` (
`aid` bigint(20) unsigned NOT NULL auto_increment,
`id` int(10) unsigned NOT NULL default '0',
`k` int(10) unsigned NOT NULL default '0',
`c` char(120) NOT NULL default '',
`pad` char(60) NOT NULL default '',
PRIMARY KEY  (`aid`),
KEY `k` (`k`),
KEY `id` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1000001 DEFAULT CHARSET=latin1
show index from sbtest;
+--------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| Table  | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+--------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| sbtest |          0 | PRIMARY  |            1 | aid         | A         |     1000099 |     NULL | NULL   |      | BTREE      |         |
| sbtest |          1 | k        |            1 | k           | A         |          18 |     NULL | NULL   |      | BTREE      |         |
| sbtest |          1 | id       |            1 | id          | A         |     1000099 |     NULL | NULL   |      | BTREE      |         |
+--------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+

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填充了 100万条记录。
1、直接 count(*)

explain SELECT COUNT(*) FROM sbtest;
+----+-------------+--------+-------+---------------+---------+---------+------+---------+-------------+
| id | select_type | table  | type  | possible_keys | key     | key_len | ref  | rows    | Extra       |
+----+-------------+--------+-------+---------------+---------+---------+------+---------+-------------+
|  1 | SIMPLE      | sbtest | index | NULL          | PRIMARY | 8       | NULL | 1000099 | Using index |
+----+-------------+--------+-------+---------------+---------+---------+------+---------+-------------+
SELECT COUNT(*) FROM sbtest;
+----------+
| COUNT(*) |
+----------+
|  1000000 |
+----------+
1 row in set (1.42 sec)

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可以看到，如果不加任何条件，那么优化器优先采用 primary key 来进行扫描。
2、count(*) 使用 primary key 字段做条件

explain SELECT COUNT(*) FROM sbtest WHERE aid>=0;
+----+-------------+--------+-------+---------------+---------+---------+------+--------+--------------------------+
| id | select_type | table  | type  | possible_keys | key     | key_len | ref  | rows   | Extra                    |
+----+-------------+--------+-------+---------------+---------+---------+------+--------+--------------------------+
|  1 | SIMPLE      | sbtest | range | PRIMARY       | PRIMARY | 8       | NULL | 485600 | Using where; Using index |
+----+-------------+--------+-------+---------------+---------+---------+------+--------+--------------------------+
SELECT COUNT(*) FROM sbtest WHERE aid>=0;
+----------+
| COUNT(*) |
+----------+
|  1000000 |
+----------+
1 row in set (1.39 sec)

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可以看到，尽管优化器认为只需要扫描 485600 条记录(其实是索引)，比刚才少多了，但其实仍然要做全表(索引)扫描。因此耗时和第一种相当。

3、 count(*) 使用 secondary index 字段做条件

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explain SELECT COUNT(*) FROM sbtest WHERE id>=0;
+----+-------------+--------+-------+---------------+------+---------+------+--------+--------------------------+
| id | select_type | table  | type  | possible_keys | key  | key_len | ref  | rows   | Extra                    |
+----+-------------+--------+-------+---------------+------+---------+------+--------+--------------------------+
|  1 | SIMPLE      | sbtest | range | id            | id   | 4       | NULL | 500049 | Using where; Using index |
+----+-------------+--------+-------+---------------+------+---------+------+--------+--------------------------+
SELECT COUNT(*) FROM sbtest WHERE id>=0;
+----------+
| COUNT(*) |
+----------+
|  1000000 |
+----------+
1 row in set (0.43 sec)

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可以看到，采用这种方式查询会非常快。
有人也许会问了，会不会是因为 id 字段的长度比 aid 字段的长度来的小，导致它扫描起来比较快呢？先不着急下结论，咱们来看看下面的测试例子。
二、 sbtest1 表上的测试

show create table sbtest1\G
*************************** 1. row ***************************
Table: sbtest1
Create Table: CREATE TABLE `sbtest1` (
`aid` int(10) unsigned NOT NULL AUTO_INCREMENT,
`id` bigint(20) unsigned NOT NULL DEFAULT '0',
`k` int(10) unsigned NOT NULL DEFAULT '0',
`c` char(120) NOT NULL DEFAULT '',
`pad` char(60) NOT NULL DEFAULT '',
PRIMARY KEY (`aid`),
KEY `k` (`k`),
KEY `id` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1000001 DEFAULT CHARSET=latin1
show index from sbtest1;
+---------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| Table   | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+---------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| sbtest1 |          0 | PRIMARY  |            1 | aid         | A         |     1000099 |     NULL | NULL   |      | BTREE      |         |
| sbtest1 |          1 | k        |            1 | k           | A         |          18 |     NULL | NULL   |      | BTREE      |         |
| sbtest1 |          1 | id       |            1 | id          | A         |     1000099 |     NULL | NULL   |      | BTREE      |         |
+---------+------------+----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+

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这个表里，把 aid 和 id 的字段长度调换了一下，也填充了 1000万条记录。
1、直接 count(*)

explain SELECT COUNT(*) FROM sbtest1;
+----+-------------+---------+-------+---------------+---------+---------+------+---------+-------------+
| id | select_type | table   | type  | possible_keys | key     | key_len | ref  | rows    | Extra       |
+----+-------------+---------+-------+---------------+---------+---------+------+---------+-------------+
|  1 | SIMPLE      | sbtest1 | index | NULL          | PRIMARY | 4       | NULL | 1000099 | Using index |
+----+-------------+---------+-------+---------------+---------+---------+------+---------+-------------+
SELECT COUNT(*) FROM sbtest1;
+----------+
| COUNT(*) |
+----------+
|  1000000 |
+----------+
1 row in set (1.42 sec)

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可以看到，如果不加任何条件，那么优化器优先采用 primary key 来进行扫描。
2、count(*) 使用 primary key 字段做条件

explain SELECT COUNT(*) FROM sbtest1 WHERE aid>=0;
+----+-------------+---------+-------+---------------+---------+---------+------+--------+--------------------------+
| id | select_type | table   | type  | possible_keys | key     | key_len | ref  | rows   | Extra                    |
+----+-------------+---------+-------+---------------+---------+---------+------+--------+--------------------------+
|  1 | SIMPLE      | sbtest1 | range | PRIMARY       | PRIMARY | 4       | NULL | 316200 | Using where; Using index |
+----+-------------+---------+-------+---------------+---------+---------+------+--------+--------------------------+
1 row in set (0.00 sec)
SELECT COUNT(*) FROM sbtest1 WHERE aid>=0;
+----------+
| COUNT(*) |
+----------+
|  1000000 |
+----------+
1 row in set (1.42 sec)

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可以看到，尽管优化器认为只需要扫描 485600 条记录(其实是索引)，比刚才少多了，但其实仍然要做全表(索引)扫描。因此耗时和第一种相当。

3、 count(*) 使用 secondary index 字段做条件

explain SELECT COUNT(*) FROM sbtest1 WHERE id>=0;
+----+-------------+---------+-------+---------------+------+---------+------+--------+--------------------------+
| id | select_type | table   | type  | possible_keys | key  | key_len | ref  | rows   | Extra                    |
+----+-------------+---------+-------+---------------+------+---------+------+--------+--------------------------+
|  1 | SIMPLE      | sbtest1 | range | id            | id   | 8       | NULL | 500049 | Using where; Using index |
+----+-------------+---------+-------+---------------+------+---------+------+--------+--------------------------+
1 row in set (0.00 sec)
SELECT COUNT(*) FROM sbtest1 WHERE id>=0;
+----------+
| COUNT(*) |
+----------+
|  1000000 |
+----------+
1 row in set (0.45 sec)

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可以看到，采用这种方式查询会非常快。
上面的所有测试，均在 mysql 5.1.24 环境下通过，并且每次查询前都重启了 mysqld。
可以看到，把 aid 和 id 的长度调换之后，采用 secondary index 查询仍然是要比用 primary key 查询来的快很多。看来主要不是字段长度引起的索引扫描快慢，而是采用 primary key 以及 secondary index 引起的区别。那么，为什么用 secondary index 扫描反而比 primary key 扫描来的要快呢？我们就需要了解innodb的? clustered index?和 secondary index?之间的区别了。
innodb 的 clustered index 是把 primary key 以及 row data 保存在一起的，而 secondary index 则是单独存放，然后有个指针指向 primary key。因此，需要进行 count(*) 统计表记录总数时，利用 secondary index 扫描起来，显然更快。而primary key则主要在扫描索引，同时要返回结果记录时的作用较大，例如：

SELECT * FROM sbtest WHERE aid = xxx;

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那既然是使用 secondary index 会比 primary key 更快，为何优化器却优先选择 primary key 来扫描呢， Heikki Tuuri?的回答是：

in the example table, the secondary index is inserted into in a perfect order! That is
very unusual. Normally the secondary index would be fragmented, causing random disk I/O,
and the scan would be slower than in the primary index.
I am changing this to a feature request: keep 'clustering ratio' statistics on a secondary
index and do the scan there if the order is almost the same as in the primary index. I
doubt this feature will ever be implemented, though.

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详情请看：这个 bug，以及这个文章： InnoDB Row Counting using Indexes。
最后感谢老杨的帮助。

技术相关:?

MySQL优化

InnoDB