Xamarin Android API 33+ 中 Bundle.GetParcelable 废弃问题的解决方案与类型安全迁移指南

/* @deprecated Use the type-safer {@link #getParcelable(String, Class)} starting from Android
*      {@link Build.VERSION_CODES#TIRAMISU}.
*/
@Deprecated
@Nullable
public <T extends Parcelable> T getParcelable(@Nullable String key) {
  // Implementation here
}

/**
 * Returns the value associated with the given key or {@code null} if:
 * <ul>
 *     <li>No mapping of the desired type exists for the given key.
 *     <li>A {@code null} value is explicitly associated with the key.
 *     <li>The object is not of type {@code clazz}.
 * </ul>
 *
 * @param key a String, or {@code null}
 * @param clazz The type of the object expected
 * @return a Parcelable value, or {@code null}
 */
@SuppressWarnings("unchecked")
@Nullable
public <T> T getParcelable(@Nullable String key, @NonNull Class<T> clazz) {
    // Implementation here
}

// 假设 MyUser 是一个已填充数据的 User 实例
User MyUser = new User("...", "...", /* ...其他属性... */);

Intent intent = new Intent(this, typeof(Menu));
Bundle bundlee = new Bundle();
bundlee.PutParcelable("MyUser", MyUser); // 将 User 实例存入 Bundle
intent.PutExtra("TheBundle", bundlee);
StartActivity(intent);

// 在目标 Activity 中接收 Bundle
Bundle bundlee = Intent.GetBundleExtra("TheBundle");

User MyUser = new User("", "", "", "", "", "", "", "", "", "", "", "", "", "", "", "", "", "", "", "", ""); // 初始化，但这行在实际使用中通常不是必需的，可以直接赋值
MyUser = bundlee.GetParcelable("MyUser") as User; // 废弃警告出现在这里

// 在目标 Activity 中接收 Bundle
Bundle bundlee = Intent.GetBundleExtra("TheBundle");

if (bundlee != null)
{
    // 使用新的 GetParcelable 方法，通过 Java.Lang.Class.FromType 提供类型信息
    // MyUser = bundlee.GetParcelable("MyUser", Java.Lang.Class.FromType(typeof(User))) as User;

    // 或者，如果 MyUser 实例已经存在（如通过默认构造函数创建），也可以使用其类型
    // User MyUser = new User(); // 假设 User 有一个无参构造函数
    // MyUser = bundlee.GetParcelable("MyUser", Java.Lang.Class.FromType(MyUser.GetType())) as User;

    // 更简洁和推荐的做法是直接获取并赋值
    User MyUser = bundlee.GetParcelable("MyUser", Java.Lang.Class.FromType(typeof(User))) as User;

    if (MyUser != null)
    {
        // 成功获取到 MyUser 对象，进行后续操作
        Console.WriteLine($"User Name: {MyUser.Name}"); // 假设 User 类有 Name 属性
    }
    else
    {
        Console.WriteLine("Failed to retrieve MyUser object or it was null.");
    }
}
else
{
    Console.WriteLine("Bundle is null.");
}