exists在子查询结果集庞大或只需判断存在性时性能更优,因其采用“短路”机制,逐行检查并立即返回结果;2. in适用于子查询结果集较小、非关联且可缓存的场景,此时效率高且代码更直观;3. not in存在null值陷阱,当子查询结果含null时会导致查询无结果,应优先使用not exists或left join ... where ... is null替代,以确保逻辑正确并提升性能。

解决
EXISTS
IN
EXISTS
IN
很多人在写SQL时,不自觉地就习惯性地用
IN
IN
而
EXISTS
TRUE
所以,解决办法很直接:
EXISTS
EXISTS
IN
NOT IN
NOT IN
NULL
NULL
NOT EXISTS
LEFT JOIN ... WHERE ... IS NULL
示例代码 (简单版):
IN
large_customers
SELECT * FROM orders WHERE customer_id IN (SELECT id FROM large_customers WHERE status = 'inactive');
优化为 EXISTS
SELECT o.* FROM orders o WHERE EXISTS (SELECT 1 FROM large_customers lc WHERE lc.id = o.customer_id AND lc.status = 'inactive');
NOT IN
subquery_table.id
NULL
-- 可能不返回任何结果 SELECT * FROM main_table WHERE id NOT IN (SELECT id FROM subquery_table);
优化为 NOT EXISTS
LEFT JOIN
SELECT m.* FROM main_table m WHERE NOT EXISTS (SELECT 1 FROM subquery_table s WHERE s.id = m.id); -- 或者 SELECT m.* FROM main_table m LEFT JOIN subquery_table s ON m.id = s.id WHERE s.id IS NULL;
EXISTS
orders
IN
但用
EXISTS
特别是当你的子查询逻辑是判断“是否存在”而非“等于某个具体值”时,
EXISTS
-- 查找至少有一个活跃订单的客户 SELECT c.customer_name FROM customers c WHERE EXISTS (SELECT 1 FROM orders o WHERE o.customer_id = c.customer_id AND o.status = 'active');
这里,
EXISTS
customer_id
EXISTS
虽然我们总在强调
EXISTS
IN
IN
最典型的例子就是当你的子查询返回的结果集非常小,而且是固定的几个值,或者从一个很小的参照表里取值时。比如,你只想找出某个部门或者几个特定区域的员工:
-- 查找市场部和销售部的员工
SELECT employee_name FROM employees
WHERE department_id IN (101, 102);
-- 或者从一个小的部门表里取ID
SELECT e.employee_name FROM employees e
WHERE e.department_id IN (SELECT d.id FROM departments d WHERE d.department_name IN ('市场部', '销售部'));这种情况下,子查询的结果集很小,数据库处理起来非常快,甚至优化器可能会将其转换为一系列
OR
IN
此外,当子查询是独立的、非关联的,并且可以被缓存时,
IN
IN
NOT IN
NULL
如果
NOT IN
NULL
NOT IN
UNKNOWN
NOT IN
A NOT IN (B, C, D)
A <> B AND A <> C AND A <> D
NULL
A <> NULL
UNKNOWN
TRUE
FALSE
UNKNOWN
AND
UNKNOWN
这在数据清洗不彻底或者业务逻辑复杂时,非常容易踩坑,而且问题往往难以察觉。
替代方案:
NOT EXISTS
NULL
NOT IN
-- 查找没有下过订单的客户 SELECT c.customer_name FROM customers c WHERE NOT EXISTS (SELECT 1 FROM orders o WHERE o.customer_id = c.customer_id);
NOT EXISTS
FALSE
LEFT JOIN ... WHERE ... IS NULL
-- 查找没有下过订单的客户 (使用LEFT JOIN) SELECT c.customer_name FROM customers c LEFT JOIN orders o ON c.customer_id = o.customer_id WHERE o.customer_id IS NULL;
这种写法通过左连接尝试匹配,如果右表(
orders
o.customer_id
NULL
NULL
NULL
JOIN
NOT EXISTS
总的来说,为了避免不必要的麻烦,在需要“不在集合中”的逻辑时,我个人更倾向于使用
NOT EXISTS
LEFT JOIN ... IS NULL
NOT IN
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