Python怎么比较两个列表是否相等_Python列表内容比较技巧

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True

False

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list1 = [1, 2, 3]
list2 = [1, 2, 3]
list3 = [3, 2, 1]

print(list1 == list2)  # 输出: True
print(list1 == list3)  # 输出: False

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__eq__

__eq__

class MyObject:
    def __init__(self, value):
        self.value = value

    def __eq__(self, other):
        if isinstance(other, MyObject):
            return self.value == other.value
        return False

obj1 = MyObject(1)
obj2 = MyObject(1)
obj3 = MyObject(2)

list1 = [obj1, obj2]
list2 = [obj1, obj2]
list3 = [obj1, obj3]

print(list1 == list2) # 输出: True (因为MyObject定义了比较规则)
print(list1 == list3) # 输出: False

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list1 = [1, 2, 3]
list2 = [3, 1, 2]

print(sorted(list1) == sorted(list2)) # 输出: True

set

set

set

list1 = [[1, 2], [3, 4]]
list2 = [[3, 4], [1, 2]]

set1 = set(tuple(x) for x in list1)
set2 = set(tuple(x) for x in list2)

print(set1 == set2) # 输出: True

hashlib

import numpy as np

list1 = [1, 2, 3, 4, 5] * 100000
list2 = [1, 2, 3, 4, 5] * 100000

array1 = np.array(list1)
array2 = np.array(list2)

print(np.array_equal(array1, array2)) # 输出: True

np.array_equal

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itertools.zip_longest

import itertools

list1 = [1, 2, 3]
list2 = [1, 2]

for a, b in itertools.zip_longest(list1, list2, fillvalue=None):
    if a != b:
        print("列表不相等")
        break
else:
    print("列表相等") # 如果循环没有被break，则执行else

zip_longest

fillvalue

list1 = [[1, 2]]
list2 = list1  # list2 指向 list1 的同一个对象

list2[0][0] = 3

print(list1) # 输出: [[3, 2]] (list1 也被修改了)
print(list2) # 输出: [[3, 2]]

copy.deepcopy

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math.isclose