解决DataJpaTest中集合断言失败：理解isEqualTo与集合类型差异

expected: "[com.example.recipesapi.model.Recipe@45f421c] (List12@14983265)"
 but was: "[com.example.recipesapi.model.Recipe@45f421c] (ArrayList@361483eb)"

@DataJpaTest
class RecipeRepositoryTest {

    @Autowired
    private RecipeRepository recipeRepositoryUnderTest;

    // 确保每个测试前清空数据，实现测试隔离
    @BeforeEach
    void tearDown() {
        recipeRepositoryUnderTest.deleteAll();
    }

    @Test
    void shouldFindSingleRecipeByName() {
        //given
        String searchName = "Tomato soup";

        Recipe recipe1 = new Recipe(1L, "Tomato soup", "Delicious tomato soup", Arrays.asList("1. "), Arrays.asList("1. "));
        Recipe recipe2 = new Recipe(2L, "Mushrooms soup", "Delicious mushrooms soup", Arrays.asList("1. "), Arrays.asList("2. "));

        List<Recipe> recipes = List.of(recipe1, recipe2); // 使用List.of()创建不可变列表

        recipeRepositoryUnderTest.saveAll(recipes);

        //when
        List<Recipe> recipesList = recipeRepositoryUnderTest.findRecipeByName(searchName.toLowerCase());

        //then
        // 这里的isEqualTo可能导致类型不匹配问题
        assertThat(recipesList).isEqualTo(List.of(recipe1)); 
    }

    // 其他测试方法...
}

import static org.assertj.core.api.Assertions.assertThat;
// ...

@Test
void shouldFindSingleRecipeByName_UsingContainsExactly() {
    // ... (given 和 when 部分保持不变)

    //then
    // 推荐使用 containsExactly 比较集合内容
    assertThat(recipesList).containsExactly(recipe1); 
}

@Test
void shouldFindTwoRecipesByName_UsingContainsExactlyInAnyOrder() {
    // ... (given 和 when 部分保持不变)

    //then
    // 如果顺序不重要，可以使用 containsExactlyInAnyOrder
    assertThat(recipesList).containsExactlyInAnyOrder(recipe1, recipe2);
}

import java.util.ArrayList;
import java.util.List;
// ...

@Test
void shouldFindSingleRecipeByName_StandardizingCollectionType() {
    // ... (given 和 when 部分保持不变)

    //then
    // 将预期的List.of()结果包装成ArrayList
    assertThat(recipesList).isEqualTo(new ArrayList<>(List.of(recipe1))); 
}

@Override
public boolean equals(final Object o) {
    if (this == o) return true;
    if (o == null || Hibernate.getClass(this) != Hibernate.getClass(o)) return false;
    final Recipe recipe = (Recipe) o;
    return id != null && Objects.equals(id, recipe.id);
}

@Override
public int hashCode() {
    return getClass().hashCode(); // ⚠️ 潜在问题：与equals不一致
}

import java.util.Objects;
// ...

@Override
public boolean equals(final Object o) {
    if (this == o) return true;
    if (o == null || Hibernate.getClass(this) != Hibernate.getClass(o)) return false;
    final Recipe recipe = (Recipe) o;
    // 对于JPA实体，通常只比较ID即可
    return id != null && Objects.equals(id, recipe.id);
}

@Override
public int hashCode() {
    // 与equals方法保持一致，基于id字段计算哈希值
    return Objects.hash(id); 
}