开发PHP RESTful API需理解HTTP协议与REST设计原则,使用GET、POST、PUT、DELETE等方法操作资源。2. 项目结构应包含入口文件index.php、数据库配置、模型和响应工具。3. 通过.htaccess实现URL重写,统一请求入口。4. index.php解析请求路径与方法,调用对应逻辑处理并返回JSON格式数据。

开发PHP RESTful API,核心是理解HTTP协议与后端逻辑的结合。你需要用PHP处理请求、返回标准格式的数据(通常是JSON),并遵循REST设计原则。下面从基础结构到实际编码一步步说明如何开发一个简单但规范的PHP RESTful API。
REST(Representational State Transfer)是一种设计风格,不是强制标准。它利用HTTP动词来操作资源:
例如,对用户资源的操作:
建议使用简洁的目录结构:
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api/确保服务器支持重写规则(如Apache的mod_rewrite),使用.htaccess隐藏index.php:
RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^(.*)$ index.php?path=$1 [QSA,L]
这是所有请求的统一入口,负责解析路径和方法:
```php json; charset=UTF-8"); header("Access-Control-Allow-Origin: *"); header("Access-Control-Allow-Methods: GET, POST, PUT, DELETE, PATCH"); header("Access-Control-Allow-Headers: Content-Type");$path = $_GET['path'] ?? ''; $method = $_SERVER['REQUEST_METHOD'];
require_once 'config/database.php'; require_once 'models/User.php';
$user = new User($pdo);
switch ($path) { case '': if ($method === 'GET') { echo json_encode($user->getAll()); } else { http_response_code(405); echo json_encode(['error' => 'Method not allowed']); } break;
case 'users':
if ($method === 'GET') {
echo json_encode($user->getAll());
} elseif ($method === 'POST') {
$data = json_decode(file_get_contents('php://input'), true);
$result = $user->create($data);
echo json_encode($result);
} else {
http_response_code(405);
echo json_encode(['error' => 'Method not supported']);
}
break;
case preg_match('/^users\/(\d+)$/', $path, $matches) ? $path : null:
$id = $matches[1];
if ($method === 'GET') {
$result = $user->getById($id);
echo $result ? json_encode($result) : json_encode(['error' => 'Not found']);
} elseif ($method === 'PUT') {
$data = json_decode(file_get_contents('php://input'), true);
$result = $user->update($id, $data);
echo json_encode(['success' => $result]);
} elseif ($method === 'DELETE') {
$result = $user->delete($id);
echo json_encode(['success' => $result]);
} else {
http_response_code(405);
echo json_encode(['error' => 'Method not allowed']);
}
break;
default:
http_response_code(404);
echo json_encode(['error' => 'Route not found']);}
<H3>4. 数据库与模型设计</H3>
<p>以MySQL为例,先创建用户表:</p>
```sql
CREATE TABLE users (
id INT AUTO_INCREMENT PRIMARY KEY,
name VARCHAR(100) NOT NULL,
email VARCHAR(100) UNIQUE NOT NULL,
created_at TIMESTAMP DEFAULT CURRENT_TIMESTAMP
);在User.php中封装CRUD操作:
public function __construct($pdo) {
$this->pdo = $pdo;
}
public function getAll() {
$stmt = $this->pdo->query("SELECT id, name, email, created_at FROM users");
return $stmt->fetchAll(PDO::FETCH_ASSOC);
}
public function getById($id) {
$stmt = $this->pdo->prepare("SELECT id, name, email, created_at FROM users WHERE id = ?");
$stmt->execute([$id]);
return $stmt->fetch(PDO::FETCH_ASSOC);
}
public function create($data) {
$stmt = $this->pdo->prepare("INSERT INTO users (name, email) VALUES (?, ?)");
try {
$stmt->execute([$data['name'], $data['email']]);
return ['id' => $this->pdo->lastInsertId()];
} catch (PDOException $e) {
return ['error' => 'Email already exists'];
}
}
public function update($id, $data) {
$stmt = $this->pdo->prepare("UPDATE users SET name = ?, email = ? WHERE id = ?");
return $stmt->execute([$data['name'], $data['email'], $id]);
}
public function delete($id) {
$stmt = $this->pdo->prepare("DELETE FROM users WHERE id = ?");
return $stmt->execute([$id]);
}}
<H3>5. 处理错误与返回标准格式</H3>
<p>建议统一响应结构,便于前端解析:</p>
```php
// 成功响应
{
"success": true,
"data": { ... }
}
// 错误响应
{
"success": false,
"error": "User not found"
}可创建一个工具函数来简化输出:
```php function sendResponse($data, $statusCode = 200) { http_response_code($statusCode); echo json_encode($data, JSON_UNESCAPED_UNICODE); exit; } ```基本上就这些。一个简单的PHP RESTful API并不复杂,关键是结构清晰、接口规范、安全可靠。随着需求增长,可以引入框架(如Slim、Laravel)来提升开发效率和维护性。
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