mysql视图如何在PHP中使用_PHP操作mysql视图的详细步骤

CREATE VIEW user_order_view AS
SELECT u.id, u.name, o.order_id, o.amount, o.created_at
FROM users u
JOIN orders o ON u.id = o.user_id;

$host = 'localhost';
$db   = 'your_database';
$user = 'your_username';
$pass = 'your_password';
$charset = 'utf8mb4';
<p>$dsn = "mysql:host=$host;dbname=$db;charset=$charset";
$options = [
PDO::ATTR_ERRMODE            => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC,
PDO::ATTR_EMULATE_PREPARES   => false,
];</p><p>try {
$pdo = new PDO($dsn, $user, $pass, $options);
} catch (\PDOException $e) {
throw new \PDOException($e->getMessage(), (int)$e->getCode());
}</p>

$sql = "SELECT * FROM user_order_view WHERE id = ?";
$stmt = $pdo->prepare($sql);
$stmt->execute([1]);
<p>while ($row = $stmt->fetch()) {
echo "姓名: " . $row['name'] . " | 金额: " . $row['amount'] . "\n";
}</p>

$stmt = $pdo->query("SELECT * FROM user_order_view");
$results = $stmt->fetchAll();
foreach ($results as $row) {
    print_r($row);
}

// 正确做法：更新原表
$sql = "UPDATE orders SET amount = ? WHERE order_id = ?";
$stmt = $pdo->prepare($sql);
$stmt->execute([99.99, 123]);