Java Switch语句中处理特定案例的业务逻辑验证：区分默认行为与内部校验

import java.util.Scanner;

public class TickTack {
    String[][] tickTackToe =
                        {{" ","|"," ","|"," "},
                        {"-","-","-","-","-"},
                        {" ","|"," ","|"," "},
                        {"-","-","-","-","-"},
                        {" ","|"," ","|"," "}};

    int xCoor = -1, yCoor = -1, counter = 1; // 初始化为无效坐标

    String x = "";
    Scanner in = new Scanner(System.in);

    public void play() {
        while (!x.equals("win")){
            // 打印当前棋盘
            for (int fila = 0; fila < 5; fila++) {
                for (int columna = 0; columna < 5; columna++) {
                    System.out.print(tickTackToe[fila][columna]);
                }
                System.out.println();
            }

            boolean inputProcessedSuccessfully = false; // 标记输入是否被成功处理（包括语法和业务逻辑）
            while (!inputProcessedSuccessfully) {
                System.out.print("请输入您的落子位置（例如：1,1）：");
                x = in.next();

                int tempXCoor = -1, tempYCoor = -1; // 临时存储解析出的坐标
                boolean inputSyntaxValid = false;   // 标记输入语法是否有效

                // 使用 switch 语句解析输入字符串到临时坐标
                switch (x) {
                    // 第一行
                    case "1,1" -> { tempXCoor = 0; tempYCoor = 0; inputSyntaxValid = true; }
                    case "1,2" -> { tempXCoor = 0; tempYCoor = 2; inputSyntaxValid = true; }
                    case "1,3" -> { tempXCoor = 0; tempYCoor = 4; inputSyntaxValid = true; }
                    // 第二行
                    case "2,1" -> { tempXCoor = 2; tempYCoor = 0; inputSyntaxValid = true; }
                    case "2,2" -> { tempXCoor = 2; tempYCoor = 2; inputSyntaxValid = true; }
                    case "2,3" -> { tempXCoor = 2; tempYCoor = 4; inputSyntaxValid = true; }
                    // 第三行
                    case "3,1" -> { tempXCoor = 4; tempYCoor = 0; inputSyntaxValid = true; }
                    case "3,2" -> { tempXCoor = 4; tempYCoor = 2; inputSyntaxValid = true; }
                    case "3,3" -> { tempXCoor = 4; tempYCoor = 4; inputSyntaxValid = true; }
                    default -> System.out.println("无效的输入格式，请重新输入（例如：1,1）");
                }

                // 如果输入语法有效，则进一步进行业务逻辑验证
                if (inputSyntaxValid) {
                    // 检查该位置是否已被占用
                    if (tickTackToe[tempYCoor][tempXCoor].equals(" ")) {
                        // 位置未被占用，更新全局坐标并标记成功处理
                        xCoor = tempXCoor;
                        yCoor = tempYCoor;
                        inputProcessedSuccessfully = true;
                    } else {
                        // 位置已被占用，提示用户并保持 inputProcessedSuccessfully 为 false，继续循环
                        System.out.println("该位置已被占用，请选择其他位置。");
                    }
                }
                // 如果 inputSyntaxValid 为 false (default 分支已处理)，则 inputProcessedSuccessfully 仍为 false，循环继续
            }

            // 根据轮次放置棋子
            counter++;
            if (counter % 2 == 0){
                tickTackToe[yCoor][xCoor] = "X"; // 使用大写X/O更清晰
            }else{
                tickTackToe[yCoor][xCoor] = "O";
            }
        }
        in.close(); // 关闭Scanner
    }

    public static void main(String[] args) {
        new TickTack().play();
    }
}