Java switch语句在游戏输入处理中的优化实践：避免重复与精细化错误反馈

import java.util.Scanner;

public class TickTack {
    String[][] tickTackToe =
                        {{" ","|"," ","|"," "},
                        {"-","-","-","-","-"},
                        {" ","|"," ","|"," "},
                        {"-","-","-","-","-"},
                        {" ","|"," ","|"," "}};

    int xCoor = -1, yCoor = -1; // 初始化为无效值
    int counter = 1;
    String gameStatus = ""; // 用于控制游戏循环，可以设置为 "win", "draw", "playing"

    Scanner in = new Scanner(System.in);

    public void play() {
        while (!gameStatus.equals("win") && !gameStatus.equals("draw")){ // 游戏主循环
            // 打印当前棋盘
            for (int fila = 0; fila < 5; fila++) {
                for (int columna = 0; columna < 5; columna++) {
                    System.out.print(tickTackToe[fila][columna]);
                }
                System.out.println();
            }

            boolean inputAccepted = false; // 标志位，表示是否成功接收并处理了有效输入
            int tempX = -1, tempY = -1;    // 临时存储解析出的坐标

            while (!inputAccepted) {
                System.out.print("请输入您的选择 (例如: 1,1): ");
                String userInput = in.next();
                boolean isValidInputFormat = false; // 标志位，表示输入格式是否有效

                // 使用 switch 语句解析输入并映射到临时坐标
                switch (userInput) {
                    // 第一行
                    case "1,1" -> { tempY = 0; tempX = 0; isValidInputFormat = true; }
                    case "1,2" -> { tempY = 0; tempX = 2; isValidInputFormat = true; }
                    case "1,3" -> { tempY = 0; tempX = 4; isValidInputFormat = true; }
                    // 第二行
                    case "2,1" -> { tempY = 2; tempX = 0; isValidInputFormat = true; }
                    case "2,2" -> { tempY = 2; tempX = 2; isValidInputFormat = true; }
                    case "2,3" -> { tempY = 2; tempX = 4; isValidInputFormat = true; }
                    // 第三行
                    case "3,1" -> { tempY = 4; tempX = 0; isValidInputFormat = true; }
                    case "3,2" -> { tempY = 4; tempX = 2; isValidInputFormat = true; }
                    case "3,3" -> { tempY = 4; tempX = 4; isValidInputFormat = true; }
                    default -> System.out.println("无效的选项，请输入正确的坐标格式 (例如: 1,1)。");
                }

                // 如果输入格式有效，则进一步检查位置是否被占用
                if (isValidInputFormat) {
                    // 检查棋盘位置是否为空 (使用 trim() 确保空格也被认为是空)
                    if (!tickTackToe[tempY][tempX].trim().isEmpty()) {
                        System.out.println("该位置已被占用，请选择其他位置。");
                        // inputAccepted 仍然为 false，内层循环继续
                    } else {
                        // 位置有效且未被占用，更新游戏坐标，并接受输入
                        yCoor = tempY;
                        xCoor = tempX;
                        inputAccepted = true; // 退出内层循环
                    }
                }
                // 如果 isValidInputFormat 为 false (default 触发)，inputAccepted 仍为 false，内层循环继续。
            }

            // 根据轮次放置棋子
            counter++; // 第一次进入循环时 counter=1，在此处变为2，所以偶数是X，奇数是O
            String playerPiece = (counter % 2 == 0) ? "X" : "O";
            tickTackToe[yCoor][xCoor] = playerPiece;

            // TODO: 在这里添加胜利条件和平局条件的检查
            // 例如：if (checkWin(playerPiece)) { gameStatus = "win"; }
            //       else if (checkDraw()) { gameStatus = "draw"; }
        }
        // 游戏结束后的处理，例如打印最终棋盘和胜者信息
        System.out.println("游戏结束！");
        // ... 打印最终棋盘 ...
    }

    public static void main(String[] args) {
        TickTack game = new TickTack();
        game.play();
    }
}