Django项目：如何为模型数据创建动态RSS Feed_在Django中为模型数据创建动态RSS Feed

from django.db import models
<p>class Post(models.Model):
title = models.CharField(max_length=200)
content = models.TextField()
pub_date = models.DateTimeField(auto_now_add=True)
is_published = models.BooleanField(default=True)</p><pre class='brush:php;toolbar:false;'>def get_absolute_url(self):
    return f"/blog/{self.id}/"

from django.contrib.syndication.views import Feed
from django.urls import reverse
from .models import Post
<p>class LatestPostsFeed(Feed):
title = "我的博客最新文章"
link = "/blog/feed/"
description = "获取最新的博客文章更新"</p><pre class='brush:php;toolbar:false;'>def items(self):
    return Post.objects.filter(is_published=True).order_by('-pub_date')[:10]

def item_title(self, item):
    return item.title

def item_description(self, item):
    return item.content[:200]  # 只显示前200字符

def item_pubdate(self, item):
    return item.pub_date

def item_link(self, item):
    return item.get_absolute_url()

from django.urls import path
from . import views
from .feeds import LatestPostsFeed
<p>app_name = 'blog'
urlpatterns = [
path('', views.post_list, name='post_list'),
path('feed/', LatestPostsFeed(), name='rss_feed'),
]</p>

from django.contrib import admin
from django.urls import include, path
<p>urlpatterns = [
path('admin/', admin.site.urls),
path('blog/', include('blog.urls')),
]</p>

<link rel="alternate" type="application/rss+xml" href="{% url 'blog:rss_feed' %}" title="订阅最新文章">

def title(self):
    return f"最近发布的 {self.items().count()} 篇文章"