在Java中如何使用sorted对集合排序_Stream排序技巧说明

List numbers = Arrays.asList(5, 2, 8, 1);

List sorted = numbers.stream()

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  .sorted()

  .collect(Collectors.toList());

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// 结果：[1, 2, 5, 8]

Listwords = Arrays.asList("banana", "apple", "cherry");

List sortedWords = words.stream()

  .sorted()

  .collect(Collectors.toList());

// 结果：["apple", "banana", "cherry"]

class Person {

  private String name;

  private int age;

  // 构造方法、getter等省略

}

List people = ... ;

List sortedByAge = people.stream()

  .sorted(Comparator.comparing(Person::getAge))

  .collect(Collectors.toList());

// 按年龄升序

List result = people.stream()

  .sorted(Comparator.comparing(Person::getAge)

    .thenComparing(Person::getName))

  .collect(Collectors.toList());

List desc = numbers.stream()

  .sorted(Collections.reverseOrder())

  .collect(Collectors.toList());

// 或针对特定字段

people.stream()

  .sorted(Comparator.comparing(Person::getAge).reversed())

  .collect(Collectors.toList());

// 按年龄降序

List withNulls = Arrays.asList("apple", null, "banana");

List safeSorted = withNulls.stream()

  .sorted(Comparator.nullsFirst(String::compareTo))

  .collect(Collectors.toList());

// null 排在最前面

.sorted(Comparator.nullsLast(String::compareTo))