怎么把一个列表中选项的值传到下个php界面中
if($roomID!=null)
{
$result=mysql_query("SELECT roomID,roomtype,roomsize FROM room WHERE roomID NOT IN (SELECT roomID FROM bookingroom WHERE bookingdate='$bookingdate' AND bookingtime='$bookingtime') AND roomID='$roomID'");
$num_rows = mysql_num_rows($result);
if ($num_rows==0) {
echo "
Sorry, No result found. Please search again.
Easily find JSON paths within JSON objects using our intuitive Json Path Finder
193
<br />
echo "<td><input type=\"submit\" name=\"submit\" value=\"Book\"onClick=\"if(confirm('Are you sure you want to book this room?'))location='insert_data.php?id=".$row['roomID']."'\")/></td>";<br />
PHP怎么学习？PHP怎么入门？PHP在哪学？PHP怎么学才快？不用担心，这里为大家提供了PHP速学教程(入门到精通)，有需要的小伙伴保存下载就能学习啦！
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号
225
收藏
取消收藏
