PHP javascript表单验证未通过而表单依然提交
如题,我的情况是不输入任何数据,点击提交注册,会弹出“请输入用户名”这样的提示,点击确定后 就转到另一个页面,并只显示一句话:Column 'UserName' cannot be null。
下面是代码:
<!--
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--><?php require_once('Connections/conetion.php'); ?><?php function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
$theValue = (!get_magic_quotes_gpc()) ? addslashes($theValue) : $theValue;
switch ($theType) {
case "text":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "long":
case "int":
$theValue = ($theValue != "") ? intval($theValue) : "NULL";
break;
case "double":
$theValue = ($theValue != "") ? "'" . doubleval($theValue) . "'" : "NULL";
break;
case "date":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "defined":
$theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
break;
}
return $theValue;
}
$editFormAction = $_SERVER['PHP_SELF'];
if (isset($_SERVER['QUERY_STRING'])) {
$editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']);
}
if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) {
$insertSQL = sprintf("INSERT INTO member (UserName, Password, Email) VALUES (%s, %s, %s)",
GetSQLValueString($_POST['UserName'], "text"),
GetSQLValueString($_POST['Password'], "text"),
GetSQLValueString($_POST['Email'], "text"));
mysql_select_db($database_conetion, $conetion);
$Result1 = mysql_query($insertSQL, $conetion) or die(mysql_error());
$insertGoTo = "index.php";
if (isset($_SERVER['QUERY_STRING'])) {
$insertGoTo .= (strpos($insertGoTo, '?')) ? "&" : "?";
$insertGoTo .= $_SERVER['QUERY_STRING'];
}
header(sprintf("Location: %s", $insertGoTo));
}
?><meta http-equiv="Content-Type" content="text/html; charset=gb2312"><title></title>
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