关于php循环输出解决方案

关于php循环输出

PHP code

<!--

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-->$list="";
if(!$car['name']){
    $list= '没有任何信息！';
}else{
    $i=1;
    foreach($car['name'] as $nm){
    $list.='
    '.$nm['xm'].'
    ';
  $i++;
    }
}
print_r($list);

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PHP code

$car['name'] = array(
  array('xm' => '李强'),
  array('xm' => '李强'),
  array('xm' => '李强'),
  array('xm' => '鸿飞'),
);
$list="";
if(!$car['name']){
    $list= '没有任何信息！';
}else{
    $i=1;
    $buf = array();
    foreach($car['name'] as $nm){
      if(! isset($buf[$nm['xm']])) $buf[$nm['xm']] = '';
      $list .= "\n" . $nm['xm'] . ($buf[$nm['xm']]++) . "\n";
      $i++;
    }
}
print_r($list);
<br><font color="#e78608">------解决方案--------------------</font><br>

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PHP code

$list="";
    $car = array('name'=>array(0=>array('xm'=>'liming'),1=>array('xm'=>'bill'), 2=>array('xm'=>'bill'), 3=>array('xm'=>'bill')));
    if(!$car['name']){
        $list='Nothing';
    }else{
        $i = 1;
        foreach($car['name'] as $nm)
        {
            if(strstr($list,$nm['xm']) && $i == 1)
            {
                $list = str_replace($nm['xm'],$nm['xm'].$i,$list);
                $list .= $nm['xm'].($i+1);
                $i++;
            }else{
                if(strstr($list,$nm['xm']))
                {
                    $list .= $nm['xm'].($i+1);
                    $i++;
                }else{
                    $list .= $nm['xm'];
                }
            }
        }
    }
    print_r($list); <div class="clear"></div>

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