[新手请教]PHP写入MySQL数据库的问题
现在利用PHP 数组生成了从1-33的任选6个数字的组合数据,约100万条的数据生成了数据.TXT文件,格式如下
[1,2,3,4,5,6]
[1,2,3,4,5,7]
[1,2,3,4,5,8]
[1,2,3,4,5,9]
[1,2,3,4,5,10]
[1,2,3,4,5,11]
[1,2,3,4,5,12]
[1,2,3,4,5,13]
[1,2,3,4,5,14]
[1,2,3,4,5,15]
[1,2,3,4,5,16]
[1,2,3,4,5,17]
[1,2,3,4,5,18]
...............
现在希望将这样的数据入库.现在有数据库表HMK,结构为
"hmkid","int(11)","NO","PRI","","auto_increment"
"l1","int(10) unsigned","NO","","",""
"l2","int(10) unsigned","NO","","",""
"l3","int(10) unsigned","NO","","",""
"l4","int(10) unsigned","NO","","",""
"l5","int(10) unsigned","NO","","",""
"l6","int(10) unsigned","NO","","",""
请问如何在程序运行过程中编写PHP程序直接将数据写入数据库而不存入txt文档啊?
我的想法
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$db=new mysqli("localhost","admin","admin","ssq");
$db->query("truncate table hmk");
$info = array(1, 2, 3,4,5,6);//$info是中间生成的的组合数组.
foreach ($info as $skey=>$value){
//echo 'my array is underline:'.$key."=>".$value."</br>" ;
$query="insert into hmk(l1,l2,l3,l4,l5,l6) values($values)";
$result=$db->query($query) ;
}
if (result)
echo "good luck" ;
else echo "sorry" ;
$db->close();
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$a = range(1, 33);
$ar = combination($a, 6);
//求组合高效率的10移动法
function combination($numArr,$combineLen) {
$numCt = count($numArr);
if($combineLen > $numCt) return;
$bin = str_pad('',$combineLen,'1');
$bin = str_pad($bin,$numCt,'0',STR_PAD_RIGHT);
$find = $bin;
$rs[] = implode(' ',array_slice($numArr,0,$combineLen));
$j = 1;
while(strrev($find) != $bin) {
$k = explode('10',$find,2);
$find = $find{0} === '0' ? strrev($k[0]).'01'.$k[1] : $k[0].'01'.$k[1];
for($i=0;$i<$numCt;$i++) $rs[$j] .= $find[$i] ? $numArr[$i] . " " : '';
$j++;
}
return $rs;
}
$fp = fopen('数据.txt', 'r');
while( !feof($fp) ){
$line = trim( fget($fp) );
$sqlvalue .= '('. substr($line, 1, -1) . '),';
}
$sql = "insert into hmk(l1,l2,l3,l4,l5,l6) values ";
$sql = $sql . substr($sqlvalue, -1, 1); // 去掉末尾的 ,
$db = new mysqli("localhost","admin","admin","ssq");
$result = $db->query($sql);
if( ! $result ){
echo $db->error();
var_dump($sql);
}
<br><font color="#e78608">------解决方案--------------------</font><br>每次查询只插入一条记录效率太低了,可以批量插入,比如每次50000条:<br><br>
$data = array(array(1,2,3,4,5,6), array(1,2,3,4,57)); //先生成这样的data数组,每个元素是一组号码的数组
$idx = 0;
while($idx query($sql);
$idx += 50000;
}
$db->close();
<br><font color="#e78608">------解决方案-------------------- <div class="clear"></div></font>
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