求助，值班代码怎么写
最近在做单位的网站，基础很薄弱，很多东西都是边看书边百度摸索着做的
最近想要实现在主页上显示每天的值班人员，四天轮一次。
我写的代码如下。
$zbb0=array("张三","李四","王五")
$zbb1=array("张三1","李四1","王五1")
$zbb2=array("张三2","李四2","王五2")
$zbb3=array("张三3","李四3","王五3")
$date_time=getdate(time));
$yday=$date_time["yday"];
if ($yday%4==0){
echo "$zbb0";}
if ($yday%4==1){
echo "$zbb1";}
if ($yday%4==2){
echo "$zbb2";}
if ($yday%4==3){
echo "$zbb3";}
?>
大概意思就是获取当前日期是今年的第几天，再除以四得出余数，根据余数的数值显示相应的人员
------解决方案--------------------
$zbb0=array("张三","李四","王五");
$zbb1=array("张三1","李四1","王五1");
$zbb2=array("张三2","李四2","王五2");
$zbb3=array("张三3","李四3","王五3");
$date_time=getdate(time());
$yday=$date_time["yday"];
$day=$yday%4; //余数
$zb='zbb'.$day; //是哪天的变量
$zbb=$$zb;
print_r($zbb);
------解决方案--------------------
- PHP code
$zb=array(
1=>array("张三","李四","王五")
,array("张三1","李四1","王五1"),
array("张三2","李四2","王五2"),
array("张三3","李四3","王五3")
);
$today=date("N");
switch ($today%4)
{
case 1:
print_r($zb[1]);
break;
case 2:
print_r($zb[2]);
break;
case 3:
print_r($zb[3]);
break;
case 4:
print_r($zb[3]);
break;
}
?>
------解决方案--------------------
$zbb = array(
array("张三","李四","王五"),
array("张三1","李四1","王五1"),
array("张三2","李四2","王五2"),
array("张三3","李四3","王五3"),
);
print_r($zbb[date('z')%4]);
或
echo join(',', $zbb[date('z')%4]);
