各位大神，我是这么写的，好像不对，能帮我改改吗？谢谢！
$query = "update a,b set a.sta = '3',b.scores='b.scores+a.pname' from `member_operation` where aid = '$var' as a left join `member` as b on a.mid=b.mid ";
member_operation where aid = '$var表和member表通过 a.mid=b.mid相联。
我想使得member_operation 表中的sta = '3'，member表中的scores等于原有值加上member_operation 中pname值。
有人教我一下吗？谢谢大神。。。
UPDATE a,b set a.sta = '3',b.scores='b.scores+a.pname' from `member_operation` WHERE aid = '$var' as a left join `member` as b on a.mid=b.mid
UPDATE a,b set a.sta = '3',b.scores='b.scores+a.pname' from `member_operation` WHERE aid = '$var' as a left join `member` as b on a.mid=b.mid
UPDATE a,b set a.sta = '3',b.scores='b.scores+a.pname' from `member_operation` as a left join `member` as b on a.mid=b.mid WHERE a.aid = '$var' 试试这句吧 看看符合你需求么。。
好的 ，我试试，谢谢~！
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