php 数组合并的问题-php教程-PHP中文网

二维数组需要合并

$arr2=array(    "hdzt_show" =>       array (                        "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "speak_uv" => "39",            "speak_amount" => "67"                    ));$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"        ));

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用这个的话array_merge_recursive 前面的local_date，parent_channel 会重复生成数组

想要下面的结果

$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"			"speak_uv" => "39",            "speak_amount" => "67"        ));

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hdzt_show 这个键还有uv 这些键数量名称都是不固定的

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回复讨论(解决方案)

这个数组有上千个所以尽量快一点的方法

如果两数组规模一样，次序也一样则

$arr2=array(    "hdzt_show" =>       array (                         "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "speak_uv" => "39",            "speak_amount" => "67"                     ));$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"        ));$r = array_combine(array_keys($arr), array_map('array_merge', $arr, $arr2));var_export($r);

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若考虑到两数组可能存在规模上的差异（第一维数量不同、排列次序不同）则

foreach($arr as $k=>$v) {  if(isset($arr2[$k])) $r[$k] = array_merge($v, $arr2[$k]);}var_export($r);

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array (  'hdzt_show' =>   array (    'local_date' => '1420128000',    'parent_channel' => 'hdzt_show',    'channel' => 'hdzt_show',    'uv' => '7',    'fuv' => '6',    'valid_user' => '2',    'duration' => '586',    'register' => '0',    'third_register' => '0',    'pv' => '15',    'speak_uv' => '39',    'speak_amount' => '67',  ),)

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如果重复了你怎么处理? 假设字段重复取最后一个,并且待处理数组都是同样key的二维数组那么可以这么写

function merge_arr($arr,$key1=null){	if(!$key1) $key1= key($arr[0]);	$return_arr = array();	foreach($arr as $key=>$val){		foreach($val[$key1] as $k=>$v){			$return_arr[$key1][$k] = $v;		}		}	return $return_arr;}$arr2=array(    "hdzt_show" =>       array (                         "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "speak_uv" => "39",            "speak_amount" => "67"                     ));$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"        ));print_r(merge_arr(array($arr2,$arr)));exit;

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结果如下

Array(    [hdzt_show] => Array        (            [local_date] => 1420128000            [parent_channel] => hdzt_show            [channel] => hdzt_show            [speak_uv] => 39            [speak_amount] => 67            [uv] => 7            [fuv] => 6            [valid_user] => 2            [duration] => 586            [register] => 0            [third_register] => 0            [pv] => 15        ))

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如果两数组规模一样，次序也一样则

$arr2=array(    "hdzt_show" =>       array (                         "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "speak_uv" => "39",            "speak_amount" => "67"                     ));$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"        ));$r = array_combine(array_keys($arr), array_map('array_merge', $arr, $arr2));var_export($r);

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若考虑到两数组可能存在规模上的差异（第一维数量不同、排列次序不同）则

foreach($arr as $k=>$v) {  if(isset($arr2[$k])) $r[$k] = array_merge($v, $arr2[$k]);}var_export($r);

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array (  'hdzt_show' =>   array (    'local_date' => '1420128000',    'parent_channel' => 'hdzt_show',    'channel' => 'hdzt_show',    'uv' => '7',    'fuv' => '6',    'valid_user' => '2',    'duration' => '586',    'register' => '0',    'third_register' => '0',    'pv' => '15',    'speak_uv' => '39',    'speak_amount' => '67',  ),)

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这个可以换成多个数组合并的话要怎么改呢

如果两数组规模一样，次序也一样则

$arr2=array(    "hdzt_show" =>       array (                         "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "speak_uv" => "39",            "speak_amount" => "67"                     ));$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"        ));$r = array_combine(array_keys($arr), array_map('array_merge', $arr, $arr2));var_export($r);

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若考虑到两数组可能存在规模上的差异（第一维数量不同、排列次序不同）则

foreach($arr as $k=>$v) {  if(isset($arr2[$k])) $r[$k] = array_merge($v, $arr2[$k]);}var_export($r);

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array (  'hdzt_show' =>   array (    'local_date' => '1420128000',    'parent_channel' => 'hdzt_show',    'channel' => 'hdzt_show',    'uv' => '7',    'fuv' => '6',    'valid_user' => '2',    'duration' => '586',    'register' => '0',    'third_register' => '0',    'pv' => '15',    'speak_uv' => '39',    'speak_amount' => '67',  ),)

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这个可以换成多个数组合并的话要怎么改呢

参考我的方法把所有数组打包传进去

如果两数组规模一样，次序也一样则

$arr2=array(    "hdzt_show" =>       array (                         "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "speak_uv" => "39",            "speak_amount" => "67"                     ));$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"        ));$r = array_combine(array_keys($arr), array_map('array_merge', $arr, $arr2));var_export($r);

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若考虑到两数组可能存在规模上的差异（第一维数量不同、排列次序不同）则

foreach($arr as $k=>$v) {  if(isset($arr2[$k])) $r[$k] = array_merge($v, $arr2[$k]);}var_export($r);

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array (  'hdzt_show' =>   array (    'local_date' => '1420128000',    'parent_channel' => 'hdzt_show',    'channel' => 'hdzt_show',    'uv' => '7',    'fuv' => '6',    'valid_user' => '2',    'duration' => '586',    'register' => '0',    'third_register' => '0',    'pv' => '15',    'speak_uv' => '39',    'speak_amount' => '67',  ),)

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这个可以换成多个数组合并的话要怎么改呢

参考我的方法把所有数组打包传进去。。。说时候你这个我没看太懂麻烦给我贴一下吧还有就是你这个是俩个foreach 一共有上千条数组需要合并这样的话会不会很慢呢？

你可以用xu大的方法把数组都传进去就可以了

我这两个foreach效率不会有什么特别慢因为原理是一样的

第一层foreach就是吧你这个1000多个数组依次处理里边一层foreach是每个数组具体的处理基本思路就是每一个新的key就压入结果数组老的key就替换对应值最终的数组有所有的key 并且每个key只有一个值

好知道了你能贴一下三个数组怎么写么我是新手看不太懂你这个方法

多个数组是怎么回事（想当然的？）
如果真的是有桑前的数组需要合并的话，你就得考虑的的思路死否有问题了
如果坚持要事后合并那么应该使用 array_merge_recursive
然后对得到的结果处理一下

$arr2=array(    "hdzt_show" =>       array (                          "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "speak_uv" => "39",            "speak_amount" => "67"                      ));$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"        ));$r = array_merge_recursive($arr, $arr2);foreach($r as &$t)  foreach($t as &$v) if(is_array($v)) $v = current($v);print_r($r);

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Array(    [hdzt_show] => Array        (            [local_date] => 1420128000            [parent_channel] => hdzt_show            [channel] => hdzt_show            [uv] => 7            [fuv] => 6            [valid_user] => 2            [duration] => 586            [register] => 0            [third_register] => 0            [pv] => 15            [speak_uv] => 39            [speak_amount] => 67        ))

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$arr2=array(    "hdzt_show" =>       array (                          "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "speak_uv" => "39",            "speak_amount" => "67"                      ));$arr=array(    "hdzt_show" =>        array(            "local_date" => "1420128000",            "parent_channel" => "hdzt_show",            "channel" => "hdzt_show",            "uv" => "7",            "fuv" => "6",            "valid_user" => "2",            "duration" => "586",            "register" =>"0",            "third_register" => "0",            "pv" => "15"        ));$r = array_merge_recursive($arr, $arr2);foreach($r as &$t)  foreach($t as &$v) if(is_array($v)) $v = current($v);print_r($r);

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Array(    [hdzt_show] => Array        (            [local_date] => 1420128000            [parent_channel] => hdzt_show            [channel] => hdzt_show            [uv] => 7            [fuv] => 6            [valid_user] => 2            [duration] => 586            [register] => 0            [third_register] => 0            [pv] => 15            [speak_uv] => 39            [speak_amount] => 67        ))

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终于搞好了谢谢谢谢

谢谢俩位大牛辛苦了

谢谢楼上的俩位大牛辛苦了分不多

merge_arr(array($arr2,$arr,$arr3,$arr4,$arr5,...,$arr1000));

能帮到就好不用客气