网上搜到的代码，千篇一律是这个
Function Sort(ary)
Dim KeepChecking,I,FirstValue,SecondValue
KeepChecking = TRUE
Do Until KeepChecking = FALSE
KeepChecking = FALSE
For I = 0 to UBound(ary)
If I = UBound(ary) Then Exit For
If ary(I) > ary(I+1) Then
FirstValue = ary(I)
SecondValue = ary(I+1)
ary(I) = SecondValue
ary(I+1) = FirstValue
KeepChecking = TRUE
End If
Next
Loop
Sort = ary
End Function
存在错误。。。。。。
测试一下就知道
s="11,3,1"
s=sort(split(s,","))
for i=0 to ubound(s)
response.write s(i) & "
"
next
打印结果是
1
11
3
正确的function是:
function sort(ary)
ck=true
do Until ck = false
ck=false
For f = 0 to UBound(ary) -1
if clng(ary(f))>clng(ary(f+1)) then
v1=clng(ary(f))
v2=clng(ary(f+1))
ary(f)=v2
ary(f+1)=v1
ck=true
end if
next
loop
sort=ary
end function
就差在一个clng()
但好笑的是，有些数组，用那个错误的sort函数是可以排正确的。
java怎么学习？java怎么入门？java在哪学？java怎么学才快？不用担心，这里为大家提供了java速学教程(入门到精通)，有需要的小伙伴保存下载就能学习啦！
广告![ThinkPHP5快速开发企业站点[全程实录]](https://img.php.cn/upload/course/000/000/068/6253d918a3ce7278.png)
收藏
收藏
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号
221
