求查询优化方法-php教程-PHP中文网

求查询优化方法

php中文网

发布： 2016-06-23 14:01:12

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请问下面的代码有优化的方法吗

$catalog_1 = "select name from commodity where catalog = 1 ORDER BY rank desc LIMIT 10";$result_1 = mysql_query($catalog_1);while($row_1 = mysql_fetch_assoc($result_1)){     $response [] = $row_1;}$catalog_2 = "select name from commodity where catalog = 2 ORDER BY rank desc LIMIT 10";$result_2 = mysql_query($catalog_2);while($row_2 = mysql_fetch_assoc($result_2)){     $response [] = $row_2;}$catalog_3 = "select name from commodity where catalog = 3 ORDER BY rank desc LIMIT 10";$result_3 = mysql_query($catalog_3);while($row_3 = mysql_fetch_assoc($result_3)){     $response [] = $row_3;}$catalog_4 = "select name from commodity where catalog = 4 ORDER BY rank desc LIMIT 10";$result_4 = mysql_query($catalog_4);while($row_4 = mysql_fetch_assoc($result_4)){     $response [] = $row_4;}$catalog_5 = "select name from commodity where catalog = 5 ORDER BY rank desc LIMIT 10";$result_5 = mysql_query($catalog_5);while($row_5 = mysql_fetch_assoc($result_5)){     $response [] = $row_5;}$catalog_6 = "select name from commodity where catalog = 6 ORDER BY rank desc LIMIT 10";$result_6 = mysql_query($catalog_6);while($row_6 = mysql_fetch_assoc($result_6)){     $response [] = $row_6;}$catalog_7 = "select name from commodity where catalog = 7 ORDER BY rank desc LIMIT 10";$result_7 = mysql_query($catalog_7);while($row_7 = mysql_fetch_assoc($result_7)){     $response [] = $row_7;}$catalog_8 = "select name from commodity where catalog = 8 ORDER BY rank desc LIMIT 10";$result_8 = mysql_query($catalog_8);while($row_8 = mysql_fetch_assoc($result_8)){     $response [] = $row_8;}$catalog_11 = "select name from commodity where catalog = 11 ORDER BY rank desc LIMIT 10";$result_11 = mysql_query($catalog_11);while($row_11 = mysql_fetch_assoc($result_11)){     $response [] = $row_11;}$catalog_10 = "select name from commodity where catalog = 10 ORDER BY rank desc LIMIT 10";$result_10 = mysql_query($catalog_10);while($row_10 = mysql_fetch_assoc($result_10)){     $response [] = $row_10;}

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回复讨论(解决方案)

function getCataLog($catalog){	$catalog = "select name from commodity where catalog = ".$catalog." ORDER BY rank desc LIMIT 10";	$result = mysql_query($catalog); 	while($row = mysql_fetch_assoc($result)){	     $response [] = $row;	}}

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改写成方法

是这样调用吗 getCataLog(11);

但没数据出来

function getCataLog($catalog){    $catalog = "select name from commodity where catalog = ".$catalog." ORDER BY rank desc LIMIT 10";    $result = mysql_query($catalog);      while($row = mysql_fetch_assoc($result)){         $response [] = $row;    }    return $response;}

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还有个神奇的问题

catalog = 11 数据库有3条记录
catalog = 12 数据库有11条记录

$responses = getCataLog(11) + getCataLog(12);

这样输出应该是有14条记录的，但实标只输出了10条。而且catalog = 12的数据是从第四条开始接的

不是这么用的 php里面的 + 相比于数组的合并 array_merge 相同键值的被覆盖掉了

select name,catalog,rank from commodity c where 10 > (select count(*) from commodity where catalog=c.catalog and id>c.id) and catalog in (1,2,3,4,5,6,7,8,10,11) order by c.catalog,c.rank desc

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function getCataLog($catalog,&$response = array()){    $catalog = "select name from commodity where catalog = ".$catalog." ORDER BY rank desc LIMIT 10";    $result = mysql_query($catalog);      while($row = mysql_fetch_assoc($result)){         $response [] = $row;    }}$response = array();getCataLog(1,$response);var_dump($response);getCataLog(2,$response);var_dump($response);

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select name,catalog,rank from commodity c where 10 > (select count(*) from commodity where catalog=c.catalog and id>c.id) and catalog in (1,2,3,4,5,6,7,8,10,11) order by c.catalog,c.rank desc

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请问再加两个条件怎么加啊,我这样加了，但这样加了和数据库对不上，少了很多条数据。

$marketId = $_GET['marketId'];$cityId = $_GET['cityId'];"select name from commodity where catalog = 1 and cityId = $cityId and marketId = $marketId ORDER BY rank desc LIMIT 10""select name,catalog,rank from commodity c where 10 > (select count(*) from commodity where catalog=c.catalog and id>c.id) and catalog in (1,2,3,4,5,6,7,8,10,11) and cityId = $cityId and marketId = $marketId order by c.catalog,c.rank desc"

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