PHP 数组比较合并，求效率-php教程-PHP中文网

PHP 数组比较合并，求效率

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发布： 2016-06-23 14:13:36

原创

1623人浏览过

php 数组

$arr1 = array(1, 3, 5, 9,34,128,129);
$arr2 = array(1, 3, 6, 22,33, 128);
$arr3 = array(128,78,56,33,5,1);

想得到的结果是:
$res = array(1,128,3,5,33,9,34,129,6,22,78,56);

规则是:将3数组合并，重复度最高的往前放
//$arr1 $arr2 $arr3一定是desc就是asc排列

//如果只有$arr1和$arr2两个排序呢，或是再添个$arr4呢
//Thanks~

回复讨论(解决方案)

$arr1 = array(1, 3, 5, 9,34,128,129);$arr2 = array(1, 3, 6, 22,33, 128);$arr3 = array(128,78,56,33,5,1);$t = array_count_values(array_merge($arr1, $arr2, $arr3));arsort($t);print_r(array_keys($t));

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Array
(
    [0] => 1
    [1] => 128
    [2] => 5
    [3] => 33
    [4] => 3
    [5] => 78
    [6] => 56
    [7] => 22
    [8] => 129
    [9] => 9
    [10] => 34
    [11] => 6
)
仅用内饰函数虽然快，但并不完全符合你的要求
所以还需要自己写点代码

$t = array_count_values(array_merge($arr1, $arr2, $arr3));$res = array();for($max=max($t); $max>0; $max--)  $res = array_merge($res, array_keys($t, $max));print_r($res);

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Array
(
    [0] => 1
    [1] => 128
    [2] => 3
    [3] => 5
    [4] => 33
    [5] => 9
    [6] => 34
    [7] => 129
    [8] => 6
    [9] => 22
    [10] => 78
    [11] => 56
)

嗯，明白，还是版主给力啊~我昨晚也生搬硬套一个，
array_diff不给力啊，所以如此冗余

$arr1 = array(1,2,3,4,5,6,7,8,9,10);$arr2 = array(1,8,9,15,100);$arr3 = array(1,8,15,200);$res  = array();$resHigh	    = array();//高度相似$resMiddle	  = array();//中$resLow		 = array();//低$res	 = array_merge($arr1,$arr2,$arr3);$res	 = my_array_unique($res);				//排除重复$resHigh = array_intersect($arr1,$arr2,$arr3);	//交集$resLow  = array_merge(array_diff($arr1,$arr2,$arr3),array_diff($arr2,$arr1,$arr3),array_diff($arr3,$arr1,$arr2));//组合差集$res	 = array_diff($res,$resHigh);			//排除High$resMiddle = array_diff($res,$resLow);			//排除Low$res	 = array_merge($resHigh,$resMiddle,$resLow);function my_array_unique($array){//排除重复   $out = array();   foreach ($array as $key=>$value) {       if (!in_array($value, $out)){           $out[$key] = $value;        }   }   return $out;} echo "<pre class="brush:php;toolbar:false;">";print_r($res);exit;/*(    [0] => 1    [1] => 8    [2] => 9    [3] => 15    [4] => 2    [5] => 3    [6] => 4    [7] => 5    [8] => 6    [9] => 7    [10] => 10    [11] => 100    [12] => 200)*/

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