php json转数组出错求助-php教程-PHP中文网

php json转数组出错求助

php中文网

发布： 2016-06-23 14:23:25

原创

1605人浏览过

1：先输出json

//组合医生信息JSON$jsonDoctorInfo  = "{"mecdoctor":[";$jsonDoctorInfo .= "{"doctorId":"".$doctorId."","doctorName":"".$strDoctorName."", "doctorprice":"".$strPrice."","expertise":"".$strExpertise."","departments":"".$strdepartments."","doctorTitle":"".$strTitle."","doctorPhoto":"".$strDoctorPhoto.""}";$jsonDoctorInfo .= "]}";

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2：获取并decode
$jsonGetDoctorInfoData = json_encode($jsonGetDoctorInfoData);
$objGetDoctorInfoData = json_decode($jsonGetDoctorInfoData);
输出：

{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}

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3：将json转换成数组

//解析JSON数据	function _json_decode($json){		$comment = false;		$out = '$x=';		for ($i=0; $i<strlen($json);$i++){			if (!$comment){				if ( ($json[$i] == '{') || ($json[$i] == '[') )					$out .= ' array(';				else if (($json[$i] == '}') || ($json[$i] == ']'))					$out .= ')';				else if ($json[$i] == ':')					$out .= '=>';				else					$out .= $json[$i];          			}else				$out .= $json[$i];			if($json[$i]== '"' && $json[($i-1)]!="\")				$comment = !$comment;		}		eval($out.";");				return $x;	}

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4：出现问题
Parse error: syntax error, unexpected T_DOUBLE_ARROW in /home/u945504094/public_html/config/config.inc.php(876) : eval()'d code on line 1

回复讨论(解决方案)

请帮我看看到底是错到哪了。

$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s, true));

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Array(    [mecdoctor] => Array        (            [0] => Array                (                    [doctorId] =>                     [doctorName] => XXXX                    [doctorprice] => 122                    [expertise] => XXXXX                    [departments] => 医内科                    [doctorTitle] => 主任医师                    [doctorPhoto] => hmh                )        ))

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你并没有给出出错行附近的代码，自然也就不知道你遇到了什么问题了

谢谢版主，
我在第二步获取JSON后，将$s带入function _json_decode($json){中出现错误
4：出现问题
Parse error: syntax error, unexpected T_DOUBLE_ARROW in /home/u945504094/public_html/config/config.inc.php(876) : eval()'d code on line 1

$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s, true));

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Array(    [mecdoctor] => Array        (            [0] => Array                (                    [doctorId] =>                     [doctorName] => XXXX                    [doctorprice] => 122                    [expertise] => XXXXX                    [departments] => 医内科                    [doctorTitle] => 主任医师                    [doctorPhoto] => hmh                )        ))

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你并没有给出出错行附近的代码，自然也就不知道你遇到了什么问题了

另外请问一下，为什么我通过file_get_content获取的JSON字串，decode的时候加了true参数就没法解析成数组，但是直接将获取的json付给一个变量后测试就能转成数组呢

$urlGetDoctorInfo = "http://127.0.0.1:8080/mobileInterface/mobileDataInterface.php?Action=showDoctorInfo&doctorid=".$_REQUEST['doctorid'];$jsonGetDoctorInfoData =  file_get_contents($urlGetDoctorInfo);print_r(json_decode($jsonGetDoctorInfoData ,true));//数据就是空的//将字串穿付给变量后$s= '{"mecdoctor":[{"doctorId":"","doctorName":"XXX", "doctorprice":"122","expertise":"XXX","departments":"内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s,true));//正常输出

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请问这是为什么？

没有问题呀

$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(_json_decode($s));    function _json_decode($json){        $comment = false;        $out = '$x=';        for ($i=0; $i登录后复制

Array(    [mecdoctor] => Array        (            [0] => Array                (                    [doctorId] =>                     [doctorName] => XXXX                    [doctorprice] => 122                    [expertise] => XXXXX                    [departments] => 医内科                    [doctorTitle] => 主任医师                    [doctorPhoto] => hmh                )        ))

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是啊版主，但是用file获取的就不行。
另外请问一下，为什么我通过file_get_content获取的JSON字串，decode的时候加了true参数就没法解析成数组，但是直接将获取的json付给一个变量后测试就能转成数组呢

$urlGetDoctorInfo = "http://127.0.0.1:8080/mobileInterface/mobileDataInterface.php?Action=showDoctorInfo&doctorid=".$_REQUEST['doctorid'];$jsonGetDoctorInfoData =  file_get_contents($urlGetDoctorInfo);print_r(json_decode($jsonGetDoctorInfoData ,true));//数据就是空的//将字串穿付给变量后$s= '{"mecdoctor":[{"doctorId":"","doctorName":"XXX", "doctorprice":"122","expertise":"XXX","departments":"内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s,true));//正常输出

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请问这是为什么？

$urlGetDoctorInfo = "http://127.0.0.1:8080/mobileInterface/mobileDataInterface.php?Action=showDoctorInfo&doctorid=".$_REQUEST['doctorid'];$jsonGetDoctorInfoData =  file_get_contents($urlGetDoctorInfo);print_r(json_decode($jsonGetDoctorInfoData ,true));//数据就是空的//将字串穿付给变量后$s= '{"mecdoctor":[{"doctorId":"","doctorName":"XXX", "doctorprice":"122","expertise":"XXX","departments":"内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s,true));//正常输出版主大人，麻烦你看看这是什么问题呢，刚那个问题好了。

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没有问题呀

$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(_json_decode($s));    function _json_decode($json){        $comment = false;        $out = '$x=';        for ($i=0; $i登录后复制

Array(    [mecdoctor] => Array        (            [0] => Array                (                    [doctorId] =>                     [doctorName] => XXXX                    [doctorprice] => 122                    [expertise] => XXXXX                    [departments] => 医内科                    [doctorTitle] => 主任医师                    [doctorPhoto] => hmh                )        ))

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那是编码问题！
json_decode 只能识别 utf-8 编码的数据

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