求两个字符串的最大公共子串&最长公共子序列
<code>输入: abcbdab bdcaba</code>
<code>4</code>
即 bdcaba 与 abcbdab 的最大公共子串长度为 4
常规思路
枚举法,算出两个字符串的所有子序列,然后分别作比较,选出最大的一个子串
缺点:对于一个长度为 n 的字符串,子串个数有 2 的 n 次方个,然后在依次比较两个字符串的子串,效率过低
动态规划 LCS算法
立即学习“PHP免费学习笔记(深入)”;
以动态规划的思想来解这个题,我们用一个二位数组 $dp[][] 来存储各个字符串对应的状态,具体什么含义就不细说了,百度一下,你就知道,主要是用 PHP 实现一下
代码如下:
<code><span><span>function</span><span>lcs</span><span>(<span>$str1</span>, <span>$str2</span>)</span>
{</span><span>// 存储生成的二维矩阵</span><span>$dp</span> = <span>array</span>();
<span>// 最大子串长度</span><span>$max</span> = <span>0</span>;
<span>for</span> (<span>$i</span> = <span>0</span>; <span>$i</span> < strlen(<span>$str1</span>); <span>$i</span>++) {
<span>for</span> (<span>$j</span> = <span>0</span>; <span>$j</span> < strlen(<span>$str2</span>); <span>$j</span>++) {
<span>if</span> (<span>$str1</span>[<span>$i</span>] == <span>$str2</span>[<span>$j</span>]) {
<span>$dp</span>[<span>$i</span>][<span>$j</span>] = <span>isset</span>(<span>$dp</span>[<span>$i</span>-<span>1</span>][<span>$j</span>-<span>1</span>]) ? <span>$dp</span>[<span>$i</span>-<span>1</span>][<span>$j</span>-<span>1</span>] + <span>1</span> : <span>1</span>;
} <span>else</span> {
<span>$dp</span>[<span>$i</span>-<span>1</span>][<span>$j</span>] = <span>isset</span>(<span>$dp</span>[<span>$i</span>-<span>1</span>][<span>$j</span>]) ? <span>$dp</span>[<span>$i</span>-<span>1</span>][<span>$j</span>] : <span>0</span>;
<span>$dp</span>[<span>$i</span>][<span>$j</span>-<span>1</span>] = <span>isset</span>(<span>$dp</span>[<span>$i</span>][<span>$j</span>-<span>1</span>]) ? <span>$dp</span>[<span>$i</span>][<span>$j</span>-<span>1</span>] : <span>0</span>;
<span>$dp</span>[<span>$i</span>][<span>$j</span>] = <span>$dp</span>[<span>$i</span>-<span>1</span>][<span>$j</span>] > <span>$dp</span>[<span>$i</span>][<span>$j</span>-<span>1</span>] ? <span>$dp</span>[<span>$i</span>-<span>1</span>][<span>$j</span>] : <span>$dp</span>[<span>$i</span>][<span>$j</span>-<span>1</span>];
}
<span>$max</span> = <span>$dp</span>[<span>$i</span>][<span>$j</span>] > <span>$max</span> ? <span>$dp</span>[<span>$i</span>][<span>$j</span>] : <span>$max</span>;
}
}
<span>for</span> (<span>$i</span> = <span>0</span>; <span>$i</span> < strlen(<span>$str1</span>); <span>$i</span>++) {
<span>for</span> (<span>$j</span> = <span>0</span>; <span>$j</span> < strlen(<span>$str2</span>); <span>$j</span>++) {
<span>echo</span><span>$dp</span>[<span>$i</span>][<span>$j</span>] . <span>" "</span>;
}
<span>echo</span><span>"<br />"</span>;
}
var_dump(<span>$max</span>);
}
lcs(<span>"abcbdab"</span>, <span>"bdcaba"</span>);</code>对应输出:
<code><span>0</span><span>0</span><span>0</span><span>1</span><span>1</span><span>1</span><span>1</span><span>1</span><span>1</span><span>1</span><span>2</span><span>2</span><span>1</span><span>1</span><span>2</span><span>2</span><span>2</span><span>2</span><span>1</span><span>1</span><span>2</span><span>2</span><span>3</span><span>3</span><span>1</span><span>2</span><span>2</span><span>2</span><span>3</span><span>3</span><span>1</span><span>2</span><span>2</span><span>3</span><span>3</span><span>4</span><span>1</span><span>2</span><span>2</span><span>3</span><span>4</span><span>4</span><span>int</span><span>4</span></code>
').addClass('pre-numbering').hide(); $(this).addClass('has-numbering').parent().append($numbering); for (i = 1; i ').text(i)); }; $numbering.fadeIn(1700); }); });结论:通过动态规划,我们使时间复杂度降为了 O(nm),但是这样依旧有空间的浪费,有些数据的存储是不必要的,可以进一步做优化
以上就介绍了LCS算法&最大公共子串&最长公共子序列 PHP 实现,包括了最长公共子序列,php方面的内容,希望对PHP教程有兴趣的朋友有所帮助。
C语言怎么学习?C语言怎么入门?C语言在哪学?C语言怎么学才快?不用担心,这里为大家提供了C语言速学教程(入门到精通),有需要的小伙伴保存下载就能学习啦!
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号