foreach中使用引用引起的问题-php教程-PHP中文网

foreach中使用引用引起的问题

php中文网

发布： 2016-07-29 09:12:01

原创

1170人浏览过

废话不多说，直接看如下代码：

<span>$arr</span> = <span>array</span>(<span>'a'</span>,<span>'b'</span>,<span>'c'</span>,<span>'d'</span>);
     <span>foreach</span>(<span>$arr</span><span>as</span> &<span>$v</span>){}

     <span>foreach</span>(<span>$arr</span><span>as</span><span>$v</span>){
          var_dump(<span>$v</span>);
     }

登录后复制

运行后，结果如下：

<span>string</span><span>'a'</span> (<span>length</span>=<span>1</span>)
<span>string</span><span>'b'</span> (<span>length</span>=<span>1</span>)
<span>string</span><span>'c'</span> (<span>length</span>=<span>1</span>)
<span>string</span><span>'c'</span> (<span>length</span>=<span>1</span>)    <span> //这里为什么是c呢？</span>

登录后复制

我们会诧异，为什么最后一个是c而不是d？

其实道理很简单，在第一次循环结束以后，变量v变成了arr[3]的引用。所以，当第二次使用foreach时，使用的是传值的方式，这种方式，其实就是遍历变量arr的值，然后把值赋给变量v，由于这时候变量v是arr[3]的引用，所以把值赋给变量v，其实就是赋给arr[3]。

我们把代码改一下：

php商城系统

PHP商城系统是国内功能优秀的网上商城系统，同时也是一个商业的PHP开发框架，有多套免费模版，强大的后台管理功能，专业的网上商城系统解决方案，快速建设网上购物商城、数码商城、手机商城、办公用品商城等网站。 php商城系统v3.0 rc6升级 1、主要修复用户使用中出现的js未加载完报错问题，后台整改、以及后台栏目的全新部署、更利于用户体验。 2、扩展出，更多系统内部的功能，以便用户能够迅速找到需

查看详情

<span>$arr</span> = <span>array</span>(<span>'a'</span>,<span>'b'</span>,<span>'c'</span>,<span>'d'</span>);
     <span>foreach</span>(<span>$arr</span><span>as</span> &<span>$v</span>){}

     <span>foreach</span>(<span>$arr</span><span>as</span><span>$v</span>){
          var_dump(<span>$arr</span>);<span>//这里把变量$arr打印出来</span>
     }

登录后复制

运行后，会发现：

array (size=<span>4</span>)
  <span>0</span> => <span>string</span><span>'a'</span> (<span>length</span>=<span>1</span>)
  <span>1</span> => <span>string</span><span>'b'</span> (<span>length</span>=<span>1</span>)
  <span>2</span> => <span>string</span><span>'c'</span> (<span>length</span>=<span>1</span>)
  <span>3</span> => &<span>string</span><span>'a'</span> (<span>length</span>=<span>1</span>)
array (size=<span>4</span>)
  <span>0</span> => <span>string</span><span>'a'</span> (<span>length</span>=<span>1</span>)
  <span>1</span> => <span>string</span><span>'b'</span> (<span>length</span>=<span>1</span>)
  <span>2</span> => <span>string</span><span>'c'</span> (<span>length</span>=<span>1</span>)
  <span>3</span> => &<span>string</span><span>'b'</span> (<span>length</span>=<span>1</span>)
array (size=<span>4</span>)
  <span>0</span> => <span>string</span><span>'a'</span> (<span>length</span>=<span>1</span>)
  <span>1</span> => <span>string</span><span>'b'</span> (<span>length</span>=<span>1</span>)
  <span>2</span> => <span>string</span><span>'c'</span> (<span>length</span>=<span>1</span>)
  <span>3</span> => &<span>string</span><span>'c'</span> (<span>length</span>=<span>1</span>)
array (size=<span>4</span>)
  <span>0</span> => <span>string</span><span>'a'</span> (<span>length</span>=<span>1</span>)
  <span>1</span> => <span>string</span><span>'b'</span> (<span>length</span>=<span>1</span>)
  <span>2</span> => <span>string</span><span>'c'</span> (<span>length</span>=<span>1</span>)
  <span>3</span> => &<span>string</span><span>'c'</span> (<span>length</span>=<span>1</span>)

登录后复制

可以发现，arr[3]的值一直在改变。

').addClass('pre-numbering').hide(); $(this).addClass('has-numbering').parent().append($numbering); for (i = 1; i ').text(i)); }; $numbering.fadeIn(1700); }); });

以上就介绍了foreach中使用引用引起的问题，包括了方面的内容，希望对PHP教程有兴趣的朋友有所帮助。