<code> $.ajax({
url: '/ajax.php',
type: 'POST',
contentType: 'application/json; charset=UTF-8',
crossDomain: true,
dataType: 'json',
data: JSON.stringify(data),
success: function(response) {
alert(response);
console.log(response);
$("#spinny").hide();
var data = response.hits.hits;
console.log(data);
var source = null;
if (data.length > 0) {
$("#resultsHeader").html(data.length + " Results").show();
for (var i = 0; i < data.length; i++) {
source = data[i].fields;
}
} else {
//$("#resultsHeader").html("No Results").show();
showErrorMessage("#error-container", "<strong>Ooops!</strong> No results found! Please try again.","alert-danger", true, 3000);
}
},
error: function(jqXHR, textStatus, errorThrown) {
var jso = jQuery.parseJSON(jqXHR.responseText);
error_note('section', 'error', '(' + jqXHR.status + ') ' + errorThrown + ' --<br />' + jso.error);
}
</code>以上的js的提交过程。
以下是ajax.php的代码
<code>
<?php
require_once('bootstrap.php');
$url = ELASTICSEARCH_URL.'/test/_search';
$content = file_get_contents('php://input');
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $content);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 0);
curl_setopt($ch, CURLOPT_TIMEOUT, 5000);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json', 'Content-Length: ' . strlen($content)));
$result= curl_exec($ch);
$arr = json_decode($result);
if ($arr->hits->total>0) {
foreach ($arr->hits->hits as $es) {
$source = $es->_source;
foreach ($source as $key => $value) {
echo "$key".":"."$value";
}
}
}
?>
</code>问题:js可以正常生成请求到php，但是取不到php的返回值，不管是 $result还是$key,请问这个怎么回事？
看js的报错，会得到如下的一个提示
<code>"VM2900:1 Uncaught SyntaxError: Unexpected token y in JSON at position 1"
</code><code> $.ajax({
url: '/ajax.php',
type: 'POST',
contentType: 'application/json; charset=UTF-8',
crossDomain: true,
dataType: 'json',
data: JSON.stringify(data),
success: function(response) {
alert(response);
console.log(response);
$("#spinny").hide();
var data = response.hits.hits;
console.log(data);
var source = null;
if (data.length > 0) {
$("#resultsHeader").html(data.length + " Results").show();
for (var i = 0; i < data.length; i++) {
source = data[i].fields;
}
} else {
//$("#resultsHeader").html("No Results").show();
showErrorMessage("#error-container", "<strong>Ooops!</strong> No results found! Please try again.","alert-danger", true, 3000);
}
},
error: function(jqXHR, textStatus, errorThrown) {
var jso = jQuery.parseJSON(jqXHR.responseText);
error_note('section', 'error', '(' + jqXHR.status + ') ' + errorThrown + ' --<br />' + jso.error);
}
</code>以上的js的提交过程。
以下是ajax.php的代码
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<code>
<?php
require_once('bootstrap.php');
$url = ELASTICSEARCH_URL.'/test/_search';
$content = file_get_contents('php://input');
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $content);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 0);
curl_setopt($ch, CURLOPT_TIMEOUT, 5000);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json', 'Content-Length: ' . strlen($content)));
$result= curl_exec($ch);
$arr = json_decode($result);
if ($arr->hits->total>0) {
foreach ($arr->hits->hits as $es) {
$source = $es->_source;
foreach ($source as $key => $value) {
echo "$key".":"."$value";
}
}
}
?>
</code>问题:js可以正常生成请求到php，但是取不到php的返回值，不管是 $result还是$key,请问这个怎么回事？
看js的报错，会得到如下的一个提示
<code>"VM2900:1 Uncaught SyntaxError: Unexpected token y in JSON at position 1"
</code>
php返回的值不是json格式的，js没有办法解析
echo json_encode()
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