mysql小练习：如何查询表中倒数第三日的全部数据

SELECT
    *FROM
    `employees`WHERE
    `hire_date` = (
        SELECT DISTINCT
            `hire_date`
        FROM
            `employees`
        ORDER BY
            `hire_date` DESC
        LIMIT 2,
        1)

drop table if exists `employees`;CREATE TABLE `employees` (`emp_no` int(11) NOT NULL,`birth_date` date NOT NULL,`first_name` varchar(14) NOT NULL,`last_name` varchar(16) NOT NULL,`gender` char(1) NOT NULL,`hire_date` date NOT NULL,)

INSERT INTO `employees` (
    `emp_no`,
    `birth_date`,
    `first_name`,
    `last_name`,
    `gender`,
    `hire_date`)VALUES
    (
        1,
        '2021-08-04',
        'Georgi',
        'Facello',
        'M',
        '1980-06-21'
    );INSERT INTO `employees` (
    `emp_no`,
    `birth_date`,
    `first_name`,
    `last_name`,
    `gender`,
    `hire_date`)VALUES
    (
        2,
        '2021-08-20',
        'Bezalel',
        'Simnel',
        'F',
        '1985-11-21'
    );INSERT INTO `employees` (
    `emp_no`,
    `birth_date`,
    `first_name`,
    `last_name`,
    `gender`,
    `hire_date`)VALUES
    (
        3,
        '2021-08-20',
        'Parto',
        'Bamford',
        'M',
        '1986-08-28'
    );INSERT INTO `employees` (
    `emp_no`,
    `birth_date`,
    `first_name`,
    `last_name`,
    `gender`,
    `hire_date`)VALUES
    (
        4,
        '2021-08-20',
        'Chirstian',
        'Koblick',
        'M',
        '1986-12-01'
    );