go语言如何实现单链表

type ListNode struct {
    Val int
    Next *ListNode
}

// 遍历节点
func (head *ListNode) Traverse() {
for head != nil {
fmt.Println(head.Val)
head = head.Next
}
}
// 在链表头添加新节点
func (head *ListNode) AddAtHead(val int) *ListNode {
node := &ListNode{
Val:  val,
Next: head,
}
return node
}
// 在链表尾添加新节点
func (head *ListNode) AddAtTail(val int) *ListNode {
if head == nil {
return &ListNode{
Val:  val,
Next: nil,
}
}
cur := head
for cur.Next != nil {
cur = cur.Next
}
cur.Next = &ListNode{
Val:  val,
Next: nil,
}
return head
}
// 在链表指定位置插入新节点
func (head *ListNode) AddAtIndex(index, val int) *ListNode {
if index <= 0 {
return head.AddAtHead(val)
}
cur := head
for i := 0; i < index-1 && cur != nil; i++ {
cur = cur.Next
}
if cur == nil {
return head
}
node := &ListNode{
Val:  val,
Next: cur.Next,
}
cur.Next = node
return head
}
// 删除链表指定位置的节点
func (head *ListNode) DeleteAtIndex(index int) *ListNode {
if index < 0 {
return head
}
if index == 0 {
return head.Next
}
cur := head
for i := 0; i < index-1 && cur != nil; i++ {
cur = cur.Next
}
if cur == nil || cur.Next == nil {
return head
}
cur.Next = cur.Next.Next
return head
}
// 获取链表指定位置的节点值
func (head *ListNode)