I have added the numbers using an array −
int[] num = new int[] {1, 25, 1, 55, 1};Now loop through and find for 1, if 1 is there, 6 then increment the variable that counts the occurrence −
foreach(int j in num) {
if (j == 1) {
cal++;
}
}The following is the code to count the number of 1’s in the entered number.
Live Demo
using System;
public class Demo {
public static void Main() {
int cal = 0;
int[] num = new int[] {1, 25, 1, 55, 1};
Console.WriteLine("Numbers:");
for (int i = 0; i < 5; i++) {
Console.WriteLine(num[i]);
}
foreach (int j in num) {
if (j == 1) {
cal++;
}
}
Console.WriteLine("Number of 1's: ");
Console.WriteLine(cal);
Console.ReadLine();
}
}Numbers: 1 25 1 55 1 Number of 1's: 3
以上就是C#程序：计算输入数字中1的个数的详细内容，更多请关注php中文网其它相关文章！
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