I have added the numbers using an array −
int[] num = new int[] {1, 25, 1, 55, 1};
Now loop through and find for 1, if 1 is there, 6 then increment the variable that counts the occurrence −
foreach(int j in num) { if (j == 1) { cal++; } }
The following is the code to count the number of 1’s in the entered number.
Live Demo
using System; public class Demo { public static void Main() { int cal = 0; int[] num = new int[] {1, 25, 1, 55, 1}; Console.WriteLine("Numbers:"); for (int i = 0; i < 5; i++) { Console.WriteLine(num[i]); } foreach (int j in num) { if (j == 1) { cal++; } } Console.WriteLine("Number of 1's: "); Console.WriteLine(cal); Console.ReadLine(); } }
Numbers: 1 25 1 55 1 Number of 1's: 3
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