
我们知道,如果没有比较或条件为 true,则 CASE 语句将返回 ELSE 语句之后指定的结果。但是,如果没有 ELSE 语句,那么在这种情况下,CASE 语句将返回 NULL。下面是一个示例来演示它。
mysql> Select CASE 100
-> WHEN 150 THEN 'It is matched'
-> WHEN 200 THEN 'It is not matched'
-> END As 'It Returns NULL';
+-----------------+
| It Returns NULL |
+-----------------+
| NULL |
+-----------------+
1 row in set (0.00 sec)下面的查询使用表“Students”中的数据,返回 NULL,因为没有学生属于 WI 国家/地区。
mysql> Select SUM(CASE WHEN country = 'USA' THEN 1 ELSE 0 END) AS USA,
-> SUM(CASE WHEN country = 'UK' THEN 1 ELSE 0 END) AS UK,
-> SUM(CASE WHEN country = 'INDIA' THEN 1 ELSE 0 END) AS INDIA,
-> SUM(CASE WHEN country = 'Russia' THEN 1 ELSE 0 END) AS Russia,
-> SUM(CASE WHEN country = 'France' THEN 1 ELSE 0 END) AS France,
-> SUM(CASE WHEN country = 'NZ' THEN 1 ELSE 0 END) AS NZ,
-> SUM(CASE WHEN country = 'Australia' THEN 1 ELSE 0 END) AS Australia,
-> SUM(CASE WHEN country = 'WI' THEN 1 END) AS WI
-> From Students;
+------+------+-------+--------+--------+------+-----------+------+
| USA | UK | INDIA | Russia | France | NZ | Australia | WI |
+------+------+-------+--------+--------+------+-----------+------+
| 2 | 1 | 2 | 1 | 1 | 1 | 1 | NULL |
+------+------+-------+--------+--------+------+-----------+------+
1 row in set (0.00 sec)以上就是MySQL CASE语句在什么情况下返回NULL?的详细内容,更多请关注php中文网其它相关文章!
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