
问题
在运行时输入一个句子,并编写一段代码来计算句子中出现的单词的平均长度
解决方案
算法START
Step 1: declare character, int and double variables
Step 2: Enter any statement
Step 3: while loop
Check condition stmt[i]=getchar()) != ''
True then enter into loop
Increment I and call the function at step 5
Step 4: Print the average length return by function
From step 5
Step 5: called function calculatewordlength
i. declare and initialize
charcount=0 and wordcount=1
ii. while loop
check condition (*stmt != '
')
if it trues enter into loop
1. if(*stmt != ' ')
2. charcount++;
3. else if(*stmt == ' ')
4. wordcount++;
5. stmt++;
iii. return (double)charcount/wordcount;
STOP
程序
#include#include double calculatewordlength(const char *stmt); int main(){ char stmt[100]; int i=0; double avglen; printf("enter any statement:"); while((stmt[i]=getchar()) != ' ') i++; stmt[i]='
'; avglen=calculatewordlength(stmt); printf("average length of word is:%f.
", avglen); } double calculatewordlength(const char *stmt){ int charcount=0; int wordcount=1; while(*stmt != '
'){ if(*stmt != ' ') charcount++; else if(*stmt == ' ') wordcount++; stmt++; } return (double)charcount/wordcount; }
输出
enter any statement:Tutorials Point is the best resource for online education average length of word: 5.444444444.










