让我们通过删除表达式中的括号来创建一个简化的表达式。
Input: A string expression with bracket is as follows: (x+y)+(z+q) The output is as follows: x+y+z+q
The input is as follows: (x-y+z)-p+q The output is as follows: x-y+z-p+q
Refer an algorithm to remove the brackets from a given input.
Step 1: Declare and read the input at runtime.
Step 2: Traverse the string.
Step 3: Copy each element of the input string into new string.
Step 4: If anyone parenthesis is encountered as an element, replace it with empty space.
Following is the C program to remove the brackets from a given input −
#include<stdio.h> int main(){ int i=0,c=0,j=0; char a[100],b[100]; printf("</p><p>Enter the string :"); scanf("%s",a); while(a[i]!='\0'){ if((a[i]=='(') && (a[i-1]=='-')){ (c=0)?j=i:j=c; while(a[i]!=')'){ if(a[i+1]=='+') b[j++]='-'; else if(a[i+1]=='-') b[j++]='+'; else if(a[i+1]!=')') b[j++]=a[i+1]; i++; } c=j+1; } else if(a[i]=='(' && a[i-1]=='+'){ (c==0)?j=i:j=c; while(a[i]!=')'){ b[j++]=a[i+1]; i++; } j–; c=j+1; } else if(a[i]==')'){ i++; continue; } else { b[j++]=a[i]; } i++; } b[j]='\0'; printf("%s",b); return 0; }
执行上述程序时,会产生以下输出 -
Enter the string:(x+y)-z x+y-z
以上就是给定输入的C程序,移除括号的详细内容,更多请关注php中文网其它相关文章!
每个人都需要一台速度更快、更稳定的 PC。随着时间的推移,垃圾文件、旧注册表数据和不必要的后台进程会占用资源并降低性能。幸运的是,许多工具可以让 Windows 保持平稳运行。
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号