闰年有366天，而普通年有365天，任务是通过程序检查给定的年份是否为闰年。
判断的逻辑可以通过检查年份是否能被400或4整除来实现，但如果不能被这两个数整除，则为普通年。
示例
Input-: year=2000 Output-: 2000 is a Leap Year Input-: year=101 Output-: 101 is not a Leap year
算法
Start
Step 1 -> declare function bool to check if year if a leap year or not
bool check(int year)
IF year % 400 = 0 || year%4 = 0
return true
End
Else
return false
End
Step 2 -> In main()
Declare variable as int year = 2000
Set check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year)
Set year = 10
Set check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year);
Stop
Example
#include#include //bool to check if year if a leap year or not bool check(int year){ // If a year is multiple of 400 or multiple of 4 then it is a leap year if (year % 400 == 0 || year%4 == 0) return true; else return false; } int main(){ int year = 2000; check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year); year = 101; check(year)? printf("%d is a Leap Year",year): printf(" %d is not a Leap Year",year); return 0; }
输出
2000 is a Leap Year 101 is not a Leap Year
