按天去除重复数据,为0则取0,否则取最大的那个值_MySQL

测试数据：mysql> select * from t2;+----+--------+---------------------+------------+| id | userid | inputDate           | infoStatus |+----+--------+---------------------+------------+|  1 |      1 | 2014-07-11 00:00:00 |      20013 | |  2 |      1 | 2014-07-11 00:00:00 |          0 | |  3 |      2 | 2014-07-12 00:00:11 |      20015 | |  4 |      2 | 2014-07-12 00:00:22 |      20013 | |  5 |      2 | 2014-07-14 00:00:00 |          0 | |  6 |      2 | 2014-07-15 00:00:00 |      20013 | |  7 |      2 | 2014-07-15 00:00:00 |          0 | |  8 |      2 | 2014-07-16 00:00:00 |          0 | |  9 |      2 | 2014-07-13 00:00:00 |      20013 | | 10 |      2 | 2014-07-13 00:00:00 |          0 | | 11 |      2 | 2014-07-14 00:00:00 |          0 | +----+--------+---------------------+------------+查询sql：select id,userid,date(inputDate) as date,max(infoStatus) as m,min(infoStatus) as i,if(min(infoStatus)=0,0,max(infoStatus)) as max from t2 where infoStatus = 0 or infoStatus <= 99999 group by date;回执结果：+----+--------+------------+-------+-------+-------+| id | userid | date       | m     | i     | max   |+----+--------+------------+-------+-------+-------+|  1 |      1 | 2014-07-11 | 20013 |     0 |     0 | |  3 |      2 | 2014-07-12 | 20015 | 20013 | 20015 | |  9 |      2 | 2014-07-13 | 20013 |     0 |     0 | |  5 |      2 | 2014-07-14 |     0 |     0 |     0 | |  6 |      2 | 2014-07-15 | 20013 |     0 |     0 | |  8 |      2 | 2014-07-16 |     0 |     0 |     0 | +----+--------+------------+-------+-------+-------+我的思路是按照时间分组，并同时查询最小，跟最大的，如果最小的为0，那max字段就为0，否则就取最大的那个